After running, the MysPow is displaying as NaN, any ideas as to why?
1 view (last 30 days)
Show older comments
KWatts = [100 500 900];
Ohms100 = [1.1900, 1.1845, 1.1776, 1.1746, 1.1797, 1.1925];
Ohms100Avg = median(Ohms100);
Ohms500 = [1.0272; 1.0292; 1.0243; 1.0212; 1.0235; 1.0241; 1.0249; 1.0245; 1.0208; 1.0167; 1.0194];
Ohms500Avg = median(Ohms500);
Ohms900 = [0.8770, 0.8730, 0.8721, 0.8676, 0.8668, 0.8675, 0.8681, 0.8661, 0.8637, 0.8617, 0.8597];
Ohms900Avg = median(Ohms900);
OhmsMys = [0.9694, 0.9770, 0.9762, 0.9814, 0.9846, 0.9839, .9932, .9928, .9919, .9954, .9964, .9870, .9841];
OhmsMysAvg = median(OhmsMys);
Ohms = [Ohms100Avg, Ohms500Avg, Ohms900Avg];
MysPow = interp1(KWatts, Ohms, OhmsMysAvg);
0 Comments
Answers (1)
Walter Roberson
on 22 Apr 2022
KWatts = [100 500 900];
Ohms100 = [1.1900, 1.1845, 1.1776, 1.1746, 1.1797, 1.1925];
Ohms100Avg = median(Ohms100);
Ohms500 = [1.0272; 1.0292; 1.0243; 1.0212; 1.0235; 1.0241; 1.0249; 1.0245; 1.0208; 1.0167; 1.0194];
Ohms500Avg = median(Ohms500);
Ohms900 = [0.8770, 0.8730, 0.8721, 0.8676, 0.8668, 0.8675, 0.8681, 0.8661, 0.8637, 0.8617, 0.8597];
Ohms900Avg = median(Ohms900);
OhmsMys = [0.9694, 0.9770, 0.9762, 0.9814, 0.9846, 0.9839, .9932, .9928, .9919, .9954, .9964, .9870, .9841];
OhmsMysAvg = median(OhmsMys);
Ohms = [Ohms100Avg, Ohms500Avg, Ohms900Avg];
MysPow = interp1(KWatts, Ohms, OhmsMysAvg);
numel(MysPow)
nnz(isnan(MysPow))
[min(KWatts), max(KWatts)]
[min(OhmsMysAvg), max(OhmsMysAvg)]
Your queiry position of 0.9846 is outside the range of index values for the input, 100 to 900. interp1() by default returns nan for values out of range.
If we examine the variable names, we would note that your index value is in kilowatts, and your dependent value is in Ohms, but your query value is in Ohms. Your query value needs to be in the same units as the corresponding index parameter, so kilowatts in this case.
If you want to use ohms values to look up kilowatt values, then the indexing vector (first parameter) would have to be ohms rather than kilowatts.
0 Comments
See Also
Categories
Find more on Matrix Indexing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!