How to plot a point, if it lies within a cube?

Hello MATLAB Community,

Say I have a point 'A' whose coordinates are [116, 6.63, 22].

Now I want create a boundary cube whose center of origin is (0,0,0) and the cube must be from -150 to +150 in X,Y,Z direction.

I would only like to plot the point A, if it is within the boundary condition (-150 to +150).

My question is how do you create a boundary cube and tell matlab to plot the point, only if its within the boundary limit?

I was not able to create a boundary for this problem.

Can anyone please help me with any suggestions.

Thank you in advance!!

I really appreciate your help.

Kind regards,

Shiv

Answer 1

[David Hill]

a = -pi : pi/2 : pi;                               
ph = pi/4;  
ampl=150;
x = ampl*[cos(a+ph); cos(a+ph)]/cos(ph);
y = ampl*[sin(a+ph); sin(a+ph)]/sin(ph);
z = ampl*[-ones(size(a)); ones(size(a))];
figure
surf(x, y, z, 'FaceColor','g','FaceAlpha',0.1)                      
hold on
grid on
A=[116, 6.63, 22];
if all(abs(A)<=ampl)
    plot3(A(1),A(2),A(3),'o','Color','b','MarkerSize',5,'MarkerFaceColor','b');
end

[Shiv Karpoor]

Hi David Hill,

Thank you for the solution of the example.

I was expecting something of this solution for my script.

I really appreciate your help!!

Answer 2

[Fangjun Jiang]

For boundary, use plot3() to plot the lines between the 8 tip points of the cube.

To check if a point is within the boundary, you just need to check if all the coordinates (x,y,z) are within the range of [-150, 150]

[Shiv Karpoor]

Hi Fangjun Jiang, I don't want to manully cross check it. hence I mentioned if statement in the question, Thank you for your response.