to form a helix spiral

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Kundan Prasad
Kundan Prasad on 13 Jan 2022
Commented: Voss on 13 Jan 2022
Dear all
I am unable to for a helix spiral using attached code.
First i want to mirror the generated curve in opposite direction and then i want a helix spiral to be formed with certain height and with certain gap. The gap can be taken as 0.5 and height as 60 mm.
The code is attached below.
Thank you
clc
R=30; %% radius of curvature
W=0.0125; %% width of grating
r=10; %% radius of workpiece
th_1=(asin(W/R)); %% angle at which blazed grating existd
th_2=2*(asin(r/R)); %% angle at which primary profile exists
n=round(degr_2/degr); %% number of grating
for i=1:n
th (i)= (((i*th_1)-((th_2)/2)));
x(i)= -(R*cos(th (i)));
z(i)= (R*sin(th (i)));
end
X1=x;
Z1=z;
figure (1)
plot(X1,Z1); hold on

Accepted Answer

Voss
Voss on 13 Jan 2022
Edited: Voss on 13 Jan 2022
clc
R=30; %% radius of curvature
W=0.0125; %% width of grating
r=10; %% radius of workpiece
th_1=(asin(W/R)); %% angle at which blazed grating existd
th_2=2*(asin(r/R)); %% angle at which primary profile exists
% n=round(degr_2/degr); %% number of grating
n = 1e5;
for i=1:n
th (i)= (((i*th_1)-((th_2)/2)));
x(i)= -(R*cos(th (i)));
z(i)= (R*sin(th (i)));
end
X1=x;
Z1=z;
Y1=th;
figure (1)
% plot(X1,Z1); hold on
plot3(X1,Y1,Z1);
xlabel('x');
ylabel('th');
zlabel('z');
view([30 60])
  2 Comments
Voss
Voss on 13 Jan 2022
clc
R=30; %% radius of curvature
W=0.0125; %% width of grating
r=10; %% radius of workpiece
th_1=(asin(W/R)); %% angle at which blazed grating existd
th_2=2*(asin(r/R)); %% angle at which primary profile exists
% n=round(degr_2/degr); %% number of grating
n = (2*pi/th_1)*120;
for i=1:n
th(i) = i*th_1 - th_2/2;
x(i)= -R*cos(th(i));
z(i)= R*sin(th(i));
end
X1=x;
Z1=z;
Y1=th./(240*pi-th_2/2)*60;
figure (1)
% plot(X1,Z1); hold on
plot3(X1,Y1,Z1);
xlabel('x');
ylabel('th');
zlabel('z');
view([30 60])

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