Finding position of a multidimensional array given manual value

Hello,
I have the following:
[max_val, position] = max(sh(:)); %Gets max value of sh and provides position
[yAxInd,yCxInd,yVxInd] = ind2sub(size(sh),position); % Given position it provides me with the multidemnsional parameters
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Is there any way i can provide the value myself to then get the parameters? Something like this..
[position] = [MyInput]; % User looking for position of a particular value
[yAxInd,yCxInd,yVxInd] = ind2sub(size(sh),position); %Given position it provides me with the multidemnsional parameters
Thanks! Appreciate the help!

 Accepted Answer

Your question is a little unclear to me, but I think you mean this:
[yAxInd,yCxInd,yVxInd] = ind2sub(size(sh),find(sh==value))

4 Comments

Hi Matt! Thanks for taking the time to help me out.
What i mean is that i can use the below to provide me with the "Y,C,V" values given the position of the Max value of "sh"
[max_val, position] = max(sh(:)); %Gets max value of sh and provides position
[yAxInd,yCxInd,yVxInd] = ind2sub(size(sh),position);
But what if i know already the Max value of "sh", how can i just provide the value of "sh" to either get its position in the multidimensional array or to get the "Y,C,V" values.
Your suggestion above doesnt work. Thanks!
Your suggestion above doesnt work.
Doesn't it? It seems to in the following example.
sh=randi(100,3,3,3)
sh =
sh(:,:,1) = 22 90 69 37 69 70 19 75 77 sh(:,:,2) = 13 28 30 86 95 9 51 31 84 sh(:,:,3) = 99 30 53 10 48 56 3 92 29
value=max(sh(:)); %"i know already the Max value of sh"
[yAxInd,yCxInd,yVxInd] = ind2sub(size(sh),find(sh==value))
yAxInd = 1
yCxInd = 1
yVxInd = 3
I see, it does work, the only issue i think am having is that there are alot of result matching the value so it creates a matrix 0x1 double and i am not able to see the values...any input? Thanks!
It is of course possible that there may be no matches or many. The code has succeeded in either case.

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R2020a

Asked:

IDN
on 19 Dec 2021

Commented:

on 20 Dec 2021

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