How to index with a changing index
1 view (last 30 days)
Show older comments
Hi, I would like to construct a matrix L of size nxn that looks like below:
L = [a,b,c,0,0,0,0,...
0,a,b,c,0,0,0,...
0,0,a,b,c,0,0,...
0,0,0,a,b,c,0,...
...
0,0,0,0,...a,b,c];
I'm trying to do this without the for loop.
i = 2:n-1;
L(:,i-1:i+1) = repmat([a,b,c],n,1);
However, this doesn't give what I want, and I was warned by the complier that i is a non-scalar operator.
Is there a way to fix this?
Thank you very much!
0 Comments
Answers (1)
DGM
on 8 Dec 2021
You can try something like this:
a = 1;
b = 2;
c = 3;
A = toeplitz([a 0 0 0 0 0 0],[a b c 0 0 0 0]);
A = A(1:end-2,:)
0 Comments
See Also
Categories
Find more on Resizing and Reshaping Matrices in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!