Using multiple functions on a variable in a table

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I have a table (T) of data 365x3. With column variables A,B,C lets say. I am trying to create a new column (D) where 2 functions would be necessary for the new variable. I run into an error that the size of the left and right do not match. I have tried 3 different approaches with no success, shown below. I am not too sure how to fix this?
%Method 1
T.D = 1000 * (2834.1 - 0.29 * T.B - 0.004 * T.B.^(2.0));
idx = T.B >= 0;
T.D(idx) = 1000 * (2501 - 2.36 * T.B);
%Method 2
idx = T.B < 0;
T.D(idx) = 1000 * (2834.1 - 0.29 * T.B - 0.004 * T.B.^(2.0));
idx2 = T.B >= 0;
T.D(idx2) = 1000 * (2501 - 2.36 * T.B);
%Method 3
idx = T{:,'B'} < 0;
T{idx,'D'} = 1000 * (2834.1 - 0.29 * T{:,'B'} - 0.004 * T{:,'B'}.^(2.0));
idx2 = T{:,'B'} >= 0;
T{idx2,'D'} = 1000 * (2501 - 2.36 * T{:,'B'});

Accepted Answer

Stef1998
Stef1998 on 27 Nov 2021
A bit tedious and Im sure there might be a faster method out there but this solves the problem
T.D1 = 1000 * (2834.1 - 0.29 * T.B - 0.004 * T.B.^(2.0));
T.D1(T.B>=0) = 0;
T.D2 = 1000 * (2501 - 2.36 * T.B);
T.D2(T.B<0) = 0;
T.D = T.D1 + T.D2;

More Answers (1)

Dave B
Dave B on 26 Nov 2021
Edited: Dave B on 26 Nov 2021
How about just initializing the new table variable first (e.g. with NaN values) and then populating it using your indices?
T = table(rand(100,1));
T.Var2 = nan(height(T), 1);
T.Var2(T.Var1<.5) = -1;
T.Var2(T.Var1>=.5) = 1
T = 100×2 table
Var1 Var2 ________ ____ 0.59525 1 0.89591 1 0.3016 -1 0.94513 1 0.38489 -1 0.3707 -1 0.20688 -1 0.066268 -1 0.07012 -1 0.97702 1 0.23667 -1 0.97863 1 0.56713 1 0.9572 1 0.93443 1 0.5219 1
  2 Comments
Stef1998
Stef1998 on 27 Nov 2021
That would be similar to what i did for method one but because I use an equation that references another variable it still does not work since the left and right sides have different elements. It would read more like
T = table(rand(100,1));
T.Var2 = nan(height(T), 1);
T.Var2(T.Var1<.5) = 3.2*T.Var1;
Unable to perform assignment because the left and right sides have a different number of elements.
T.Var2(T.Var1>=.5) = 4.2*T.Var1;
Dave B
Dave B on 27 Nov 2021
Your snippet was just missing the index in the right hand side
T = table(rand(100,1));
T.Var2 = nan(height(T), 1);
ind = T.Var1<.5;
T.Var2(ind) = 3.2*T.Var1(ind);
T.Var2(~ind) = 4.2*T.Var1(~ind)
T = 100×2 table
Var1 Var2 ________ ________ 0.61477 2.582 0.022891 0.073253 0.51972 2.1828 0.40734 1.3035 0.10431 0.3338 0.50238 2.11 0.69675 2.9263 0.82957 3.4842 0.41558 1.3298 0.12382 0.39623 0.50392 2.1164 0.9992 4.1967 0.61337 2.5762 0.69751 2.9295 0.96018 4.0328 0.82302 3.4567

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