How to improve a for

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Carlos
Carlos on 11 Oct 2014
Edited: Andrei Bobrov on 11 Oct 2014
Hello, i want to do this operation:
f = -[Q(:,1)'*Q(:,1); Q(:,2)'*Q(:,2); Q(:,3)'*Q(:,3); Q(:,4)'*Q(:,4); Q(:,5)'*Q(:,5); Q(:,6)'*Q(:,6); Q(:,7)'*Q(:,7); Q(:,8)'*Q(:,8); Q(:,9)'*Q(:,9); Q(:,10)'*Q(:,10)];
i have thought to do this with a for
n=10;
i=1;
while i<n+1
f(i,1)=-[Q(:,i)'*Q(:,i)]; %save in columns
i=i+1;
end
but i think there must be some way to vectorize this easily. Could you help me?
Thank you.

Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 11 Oct 2014

More Answers (2)

Jan
Jan on 11 Oct 2014
The vectorization is better, but here is a cleaner and more efficient loop method:
f = zeros(10, 1); % pre-allocate!!!
for k = 1:10
f(k, 1) = -(Q(:,k)' * Q(:,k));
end
  2 Comments
Carlos
Carlos on 11 Oct 2014
Thank you so much. I think that the for loop is much better than mine before. Otherwise, how is the way to make the vectorization? Is it the answer of Azzi?
Jan
Jan on 11 Oct 2014
Yes, Carlos.

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Andrei Bobrov
Andrei Bobrov on 11 Oct 2014
Edited: Andrei Bobrov on 11 Oct 2014
f = -dot(Q,Q).'

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