New to matlab. Why i get this answer?

>> syms y(t) yef(t);

ymax=120*0.40680;

yef(t)= 0.95*(1/(1+(y(t)/ymax)*y(t)+(1-(1/(1+(y(t)/ymax))*ymax))));

yo=0.40680*140;

k10=2.37;

R=0.00831447;

T=395;

HA=0.08;

n1=1.51;

E1=83.3;

K1=k10*(10^10)*(HA^n1)*exp(-E1/R*T);

ode=diff(y(t),t)==-K1*yef(t);

cond=y(0)==yo;

ySol(t)=dsolve(ode,cond)

ySol(t) =7119/125

[Rik]

You can post comments here so everybody can help you. Sending me an email (misspelling my name) is not going to do anything.

If I didn't understand your question you will have to clarify it.

[Georgios Stefanis]

Sorry new to all this. Am i trying to solve that differential equation.I was expecting getting a function of t as a result and not a number.

[Rik]

I haven't checked the math, so I don't know if you should have expected something as a function of t. If you have reason to expect that, you should check the implementation step.

Answer 1

[Rik]

syms y(t) yef(t);
ymax=120*0.40680;
yef(t)= 0.95*(1/(1+(y(t)/ymax)*y(t)+(1-(1/(1+(y(t)/ymax))*ymax))));
yo=0.40680*140;
k10=2.37;
R=0.00831447;
T=395;
HA=0.08;
n1=1.51;
E1=83.3;
K1=k10*(10^10)*(HA^n1)*exp(-E1/R*T);
ode=diff(y(t),t)==-K1*yef(t);
cond=y(0)==yo;
ySol(t)=dsolve(ode,cond)

ySol(t) = 

This is what you get, because it is the solution. If you want it in a decimal form you can easily extract the numeric value:

double(ySol(t))

ans = 56.9520