make a logical matrix from an available array of numbers.

i get an array of numbers in which minimum number is 1 and maximum number is 7 , total elements in that array are 6, e.g.

A=[2 5 6 2 7 4]

I want to make a logical matrix of order 7*6 in such a way that there is only one '1' in each column and all other entries of that column are '0'. Now the numbers in array A indicate the row number at which binary '1' is to be placed. e.g. for above provided array, my logical matrix would be:

b =

     0     0     0     0     0     0
     1     0     0     1     0     0
     0     0     0     0     0     0
     0     0     0     0     0     1
     0     1     0     0     0     0
     0     0     1     0     0     0
     0     0     0     0     1     0

kindly generalize me this program. for any random array 'A'.

Thank you.

Answer 1

[Guillaume]

cols = 1:numel(A);
B = zeros(max(A), numel(A));
B(sub2ind(size(B), A, cols)) = 1

[Furqan Haider]

if there is no 7 in array A, then your code gives me 6*6 matrix, which I dont want. I need 7*6 matrix at any cost, whether there is 7 in the array or not.

Kindly suggest, and thank you.

[Guillaume]

Well, it's trivial to modify my example. Replace 2nd line with:

B = zeros(7,6);

You could have worked that out for yourself.