how to find the angle subtended from origin to the poles in complex plane?

clc
clear all
 s=tf('s');
 num=1;
 den=(s+(-65+65j))*(s-(65+65j));
 sys=num/den;
 pzmap(sys)

i want to find the angle subtended by these poles from origin?

Answer 1

[David Goodmanson]

Hello Muhammed,

it's as easy as

angle(65+65j)
angle(65-65j)

with each angle in radians subtended from the x axis, -pi < angle <= pi