how to remove [0,0,0] cell from an array

I have a 8X1 column cell array with zeros as follows
[0,0,0]
4x3 double
5x3 double
10x3 double
6x3 doubel
[0,0,0]
4x3 double
8x3 double
Each cell has Nx3 data inside. [0,0,0] is 1x3 . I want to remove the cells that includes [0,0,0] and obtain
4x3 double
5x3 double
10x3 double
6x3 double
4x3 double
8x3 double
when I use
for i = 1:8
A{i}(A{i} == 0) = [],
end
it gives an error, "Brace indexing not supported for variables this type"
Thank you in advance !!!!

 Accepted Answer

Consider:
C = {rand(2,3) rand(3,3) rand(4,3) [0 0 0] rand(5,3)}.'
C = 5×1 cell array
{2×3 double} {3×3 double} {4×3 double} {[ 0 0 0]} {5×3 double}
iszerotuple = cell2mat(cellfun(@(x) isequal(x,[0 0 0]),C,'uniform',false))
iszerotuple = 5×1 logical array
0 0 0 1 0
C = C(~iszerotuple)
C = 4×1 cell array
{2×3 double} {3×3 double} {4×3 double} {5×3 double}

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Asked:

on 16 Oct 2021

Commented:

on 18 Oct 2021

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