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find missing elements in a matrix

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Hi, I have a matrix represents code numbers.
A=[1 2 3 6 7 45 46 47 53 78 80];
B=[55.23 ,74.22]; % B is if same length of A, and contains element by element corresponding data
Say the numbers should be in the range 1:80.
How can I find the numbers which are missing in A.
eg in above case, the expected answer is missing=[4 5 8 9 ... 79]
Then to print a text file
experiment 1 results 55.23
experiment 2 results 442.23
experiment 4 data missing
.
.
experiment 79 data missing
experiment 80 results 442.2
  2 Comments
Stephen23
Stephen23 on 19 Sep 2014
Edited: Stephen23 on 19 Sep 2014
Your edit added "Then print to a text file". This is:
  • A separate topic.
  • Easy to solve yourself using any search engine.
Other users here are not paid to write your code for you, but will happily help if there is something that needs explaining or clarification.
Rashmil Dahanayake
Rashmil Dahanayake on 23 Sep 2014
^ non technical comment. Scroll down to read relevant answers.

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Accepted Answer

Stephen23
Stephen23 on 19 Sep 2014
Try setxor :
setxor(A,1:80)
  2 Comments
Stephen23
Stephen23 on 19 Sep 2014
See also Fabio Freschi's answer using setdiff .
Rashmil Dahanayake
Rashmil Dahanayake on 20 Sep 2014
see my updated answer incorporating Fabios

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More Answers (2)

Fabio Freschi
Fabio Freschi on 19 Sep 2014
Try this
A=[1 2 3 6 7 45 46 47 53 78 80];
all = 1:80;
missing = setdiff(all,A);
Fabio

Rashmil Dahanayake
Rashmil Dahanayake on 19 Sep 2014
Edited: Rashmil Dahanayake on 19 Sep 2014
Full Answer for my question asked previously. In case if someone might find it usefull
A=1:3:20; % in complete data
B=1:20; % Full index
missing = setdiff(B,A); % check for missing elements
A=strread(num2str(A),'%s')';
for ms=1:length(missing)
A=horzcat(A(1:(missing(ms)-1)),'misplaced results',A(missing(ms):end));
end
%A % verify answer

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