Help on User Defined Function
1 view (last 30 days)
Show older comments
I'm Getting this Could not determine the size of this expression. error in a very simple function, if someone can check it out and give me a hint, I would appreciate it.
The code is this:
function subPortadora = codigos(txSig,i)
%#codegen
temp = complex(zeros(15,1));
if i < 512
if i==0
temp = txSig(1:15,1);
else
temp = txSig(i*15+1:15*(i+1),1);
end
end
subPortadora = temp;
Thanks in Advance
1 Comment
Answers (2)
Nathan
on 13 Aug 2014
Edited: Nathan
on 13 Aug 2014
Why don't you just simply replace your call to codigos with:
txSig(i*15+1:15*(i+1),1)
This will still return a column vector pulled from txSig. My solution assumes that i>=0 & i<513 and is an integer.
Alternatively, if you do need the funciton check out this link with what appears to be the same problem: http://www.mathworks.com/matlabcentral/answers/92878-why-does-embedded-matlab-fail-to-detemrine-the-size-of-my-expression-in-simulink-7-2-r2008b
0 Comments
Mike Hosea
on 19 Sep 2014
Sorry we missed this question. The problem is that colon expression lengths are tricky business in MATLAB because the end point of a:b:c is not required to equal a + n*b for any integer n, and the situation is even more complicated with non-integer or extremely large values when there can also be round-off error. Try replacing
temp = txSig(i*15+1:15*(i+1),1);
with
temp = txSig(i*15+(1:15),1);
The latter makes it crystal clear that the indexing expression is 15 elements long. You shouldn't need the if/else, as that should work perfectly when i == 0.
0 Comments
See Also
Categories
Find more on Model Verification in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!