Large binned matrix reshape

5 views (last 30 days)
Avik Mahata
Avik Mahata on 8 Oct 2021
Commented: Image Analyst on 9 Oct 2021
I was trying to find a similar solution to my problem, but I couldn't find any exact solution. I have a large matrix of 2000x100, similar data is binned in to 10 different matrices. Each of the bins are 2000x10.
That matrix is right now, bin1(2000x10) bin2 (2000x10) ......... bin10(2000x10).
I am trying to reshape the such a way that it will be ,
bin1 (2000x10)
bin2 (2000x10)
.
.
.
bin10. (2000x10)
So I should be ending up with a dataset of 20000x10. The bins need to be converted in the same sequence.

Accepted Answer

Matt J
Matt J on 8 Oct 2021
Edited: Matt J on 8 Oct 2021
tmp=num2cell(reshape(yourMatrix,200,10,10),[1,2]);
result=vertcat(tmp{:});
  2 Comments
Image Analyst
Image Analyst on 9 Oct 2021
Not sure why going to a cell array, tmp, was necessary. Since you said your "data is binned in to 10 different matrices" of size 2000 x 100 (which is not large by the way) then why can't you simply combine your 10 different matrices like this:
% Vertically stack the "10 different matrices" that the user has:
allBins = vertcat(bin1, bin2, bin3, bin4, bin5, bin6, bin7, bin8, bin9, bin10);
as I suggested in my answer? Why convert each matrix into a cell array?

Sign in to comment.

More Answers (1)

Image Analyst
Image Analyst on 8 Oct 2021
Wouldn't it just be
% Vertically stack the "10 different matrices" that the user has:
allBins = vertcat(bin1, bin2, bin3, bin4, bin5, bin6, bin7, bin8, bin9, bin10);
??? Or is that not the ordering you wanted?

Categories

Find more on Matrices and Arrays in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!