How can I create variables from a matrix (4 x m), so that every column is a variable ? In the code I have 2 elements (N=2), but I need to do it also with 6, 8 10 elements.

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N=2; % elements
L=1/N;
L=zeros(1,N)+L;
y=0:L:1;
Nf=NaN;
syms x NaN
for i=1:length(y)
if i-1==0
fa(i)=NaN;
elseif i-1==1
fa(i)=NaN;
else fa(i)=0;
end
if i-1==0
fb(i)=NaN;
else
fb(i)=(x-y(i-1))/L(i-1);
end
if i+1>N+1
fc(i)=NaN;
else
fc(i)=(y(i+1)-x)/L(i);
end
if i+1>=N+1
fd(i)=Nf;
else
fd(i)=0;
end
end
f=[fa; fb; fc; fd]
  3 Comments
DGM
DGM on 2 Oct 2021
Edited: DGM on 2 Oct 2021
This is relevant.
Long story short: arrays are indexable programmatically. Variable names are not programmatically indexable without opening up a can of worms that you should want to avoid unless you actually like causing problems for yourself.
As dpb mentioned, there are options like structs or tables that might be more desirable for the way they allow you to describe and organize their contents.
Ravi Narasimhan
Ravi Narasimhan on 2 Oct 2021
Edited: Ravi Narasimhan on 2 Oct 2021
To pile on: I use tables a lot but also Map Containers for associating keys with values when appropriate.
e.g.
A = magic(4)
A = 4×4
16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1
keySet = [1,2,3,4]; % Can be almost anything including chars if desired
valueSet = {A(:,1), A(:,2), A(:,3), A(:,4)}; % Associate a value with each key
B = containers.Map(keySet, valueSet)
B =
Map with properties: Count: 4 KeyType: double ValueType: any
B(3)
ans = 4×1
3 10 6 15
B(22) = [1 0 1 0] % Add to it. The 22 is a key vs. an array element
B =
Map with properties: Count: 5 KeyType: double ValueType: any
keys(B)
ans = 1×5 cell array
{[1]} {[2]} {[3]} {[4]} {[22]}
values(B)
ans = 1×5 cell array
{4×1 double} {4×1 double} {4×1 double} {4×1 double} {[1 0 1 0]}

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