How to colormap a 3D trajectory using a 4th array
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Hello Im having some difficulties making a 3D plot, specifically w.r.t. the colormaps
I want to plot a trajectory in 3D using arrays x,y and z. I have a fourth array (a) corresponding to the acceleration at (x,y,z), it has values between [0,1]. I want the trajectory colored using the colormap('jet') based on the acceleration array.
How do I do this
Answers (1)
Ashish Gudla
on 4 Aug 2014
You can use “scatter3” function to plot your trajectory and also pass the additional arguments, the size of the point and the color of the point (which in your case is the acceleration vector). "scatter3" automatically normalizes the 5th input argument values to the current colormap and uses it.
Example:
>> t = 0:0.1:10;
>> x = 5*cos(t);
>> y = 5*sin(t);
>> z = sin(t)+cos(t)+t; % A random trajectory
>> a = rand(1,101) %acceleration values generated randomly for example
>> scatter3(x,y,z,5,a)
>> colormap(‘jet’) %change colormap to required the required one
1 Comment
Behnam Majd
on 2 Aug 2022
owoow that was so helpful , tnx a lot
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