Subdividing a matrix and pairing specific columns in the subdivisions
3 views (last 30 days)
Show older comments
Michel Nieuwoudt
on 26 Aug 2021
Commented: Michel Nieuwoudt
on 27 Aug 2021
Hi experts,
I have a matrix of 1001 columns and 6000 rows. The first column is frequency, and the rest are signal intensities of a 1000 different samples. I want to create individual xy columns for the 1000 samples (so 1000 individual xy files), with the first column as x in each and the second column as each subsequent y value.
So D=[x y1 y2 y3 .....y1000], where each of these entries is a column of 6000 datapoints and I would like xy, xy1, xy2, xy3....xy1000 where xy=6000 x 2.
How would I go about this please?
Thank you in advance!
Best wishes,
Michel
0 Comments
Accepted Answer
Image Analyst
on 26 Aug 2021
Try this:
% Create sample data
data = rand(6000, 4);
% Sort first columns
data(:, 1) = sort(data(:, 1), 'ascend');
% Now we have our data and can begin.
[rows, columns] = size(data)
freq = data(:, 1); % Frequency is column 1.
for col = 2 : columns
fileName = sprintf('Column %3d.txt', col);
fprintf('Writing column %d to "%s".\n', col, fileName);
% Create N-by-2 matrix of frequencies in column 1, then signal in column 2.
xy = [freq, data(:, col)];
% Write out data to the text file.
writematrix(xy, fileName);
end
3 Comments
Image Analyst
on 27 Aug 2021
Yes. Let's say that the names you already have are stored in a cell array variable called columnNames. Then just use that for the filename:
% Now we have our data and can begin.
[rows, columns] = size(data)
freq = data(:, 1); % Frequency is column 1.
for col = 2 : columns
fileName = sprintf('%s.csv', columnNames);
fprintf('Writing column %d to "%s".\n', col, fileName);
% Create N-by-2 matrix of frequencies in column 1, then signal in column 2.
xy = [freq, data(:, col)];
% Write out data to the text file.
writematrix(xy, fileName);
end
More Answers (1)
the cyclist
on 26 Aug 2021
Edited: the cyclist
on 26 Aug 2021
You should strongly reconsider whether you need dynamically named variables, because it is usually a terrible idea. Instead, consider making a 3-dimensional array. Then, instead of the variable xy7, you can just access xy(:,:,7). Your code will be more robust.
% Pretend input
D = rand(6000,1001);
% Initialize 3-dimensional array
xy = zeros(6000,2,1000);
% Fill first "slice" in 2nd dimension with copies x
xy(:,1,:) = repmat(D(:,1),[1 1 1000]);
% Fill second slice with y
xy(:,2,:) = reshape(D(:,2:end),6000,1,1000);
2 Comments
Image Analyst
on 26 Aug 2021
Do you think he really meant that, because like you said, that would be a terrible idea?
I thought he wanted to just save them (each xy 6000-by-2 matrix) to 1000 files or somewhere rather than in 1000 separate, individually named variables.
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!