Matlab list all files in subfolders of the same name...

Hi, all:
My file/directory structure is as follows:
tests
----dir1
--------sweep
------------results.txt
----dir2
--------sweep
------------results.txt
----dir3
--------sweep
------------results.txt
...
----dirN
--------sweep
------------results.txt
I'd love to list all "results.txt" in all subfolders named "sweep". As you may have noticed, dir1, dir2, ... dirN are different.
Can anybody give me a hand? Thanks...
Cheers Pei

Answers (5)

ls */sweep/results.txt

8 Comments

Tried, but failed. Thanks anyway...
This should have worked if you were in the 'tests' directory.
When you say it "failed", do you mean it gave an error, or an unexpected result? I am very confident that you should be able to get the "ls" command to do what you want.
Perhaps JIA needs the specific
ls tests/*/sweep/results.txt
I'm able to "ls" in Matlab (under Windows), but with the command you suggested, I only got an error message as follows:
>> ls */sweep/results.txt
*\sweep\results.txt not found.
>> dir */sweep/results.txt
*\sweep\results.txt not found.
>>
I tried "ls */sweep/results.txt" under bash in Linux (not in the workspace from a Linux Matlab ) and it works fine. However, I don't have a licensed Linux Matlab so I can't test the command here. However, anyway, under Windows Matlab, I can't do with the above command.
Any further suggestions?
I wonder if you tried the which command. The addpath() command adds all your folder and subfolder into MATLAB path temporarily. The which command should tell you all the files found.
Thanks very much.
Either genpath(pwd) doesn't work,
or genpath(pwd) is extremely slow.
Now, 5 minutes passed, nothing happend and genpath(pwd) just kept hanging there in Matlab working space.
That is weird. Do you have lots of sub-folders under \tests\? It works slow for me too but it took 2 seconds to generate a path string totaling 77k characters. Anyway, hope you know the function genapth(), addpath() and which() now.

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addpath(genpath(pwd));
which results.txt -all
or, function format of which()
files=which('results.txt','-all');
Unfortunately I'm not allowed to post my solution to a similar problem, but I can roughly summerize my approach: I made a function which looks like
myRecursiveDir(root, varargin);
and in your case you would call it like
myRecursiveDir('tests', 'dir*', 'sweep', 'results.txt');
The method then recursively fetches the list of directories/files at each level with the dir command and returns the composed filenames.
Hope this might help.

2 Comments

I am curious to know why the built-in function genpath() and which() can not do the job. Thanks!
Well, depending on the structure of your directory-tree, the number or files/folders besides the ones you want walk-through, and the frequence you query for files, genpath() becomes quite inefficient, as the size of your list of file names grows exponentially in terms of searching depth.
In our case it was definitely worth the effort to invest a quarter of an hour to implement that kind of 'guided' search.
But you are right, genpath() should work for less complex and huge directory trees. When I first read your answer I only remembered 'genpath is not suitable' (it's been a while since we were faced to that issue), I'm sorry for that. ;)

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on 2 Aug 2011

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