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how to find the time lag in cross correlation

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mustafa alnasser
mustafa alnasser on 9 May 2014
Answered: Naomi Krauzig on 12 Dec 2019
Dear All;
I am trying to find time delay using cross correlation but it does not give the right answer
my code:
[acor1,lag1]=xcorr(EE1(:,1),EE2(:,1)); % Figure(1) [~,I] = max(abs(acor1)); timeDiff1 = lag1(I)
but the answer: timeDiff1 =
what is the problem?

Answers (2)

dpb on 9 May 2014
xcorr returns a 2*M-1 cross-correlation sequence for a vector length M from lags [-M:M] w/ the zeroth-lag in the middle of the returned vector. The auto-correlation (0-lag) value is going to be the max() so you need to restrict the search to lags>=1 and as well look for the maximum away from the initial decaying self-correlation around zero that can be significant depending on the shape of the two signals.
And, of course, there's the "minor" detail that the maximum correlation may not reflect the desired lag if the two signals aren't particularly self-similar with a phase lag only the difference as opposed to some large feature in one or the other.

Naomi Krauzig
Naomi Krauzig on 12 Dec 2019
in case this is stillan open question, there is actually a function to find the delay: d = finddelay(x,y).
otherwise [r,lags] = xcorr(x,y) also returns the lags at which the correlations are computed.

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