Can you optimize this row matching code?

1 view (last 30 days)
Amir
Amir on 23 Apr 2014
Edited: Amir on 23 Apr 2014
Hi everyone,
I have a huge matrix on which I need to do some matching operation. Here's the code I have written and it works fine, but I think there is some room to make it more optimized or write another code that does the matching in less time. Could you please help me with that?
rowsMatched = find(bigMatrix(:, 1) == matchingRow(1, 1) & bigMatrix(:, 2) == matchingRow(1, 2) & bigMatrix(:, 3) == matchingRow(1, 3))
The problem with this code is that I cannot use the && operand. So, in case one of the columns do not match the program still checks the next condition. How do you think I can avoid this?
Thank you
  2 Comments
Matt Kindig
Matt Kindig on 23 Apr 2014
Is matchingRow only a 1x3 vector? Or do you loop through all rows in matchingRow?
Can you post your full code?
Amir
Amir on 23 Apr 2014
Edited: Amir on 23 Apr 2014
It's just a 1x3 vector in this case, but it could be up to 1 x 10 (in case I had a bigMatrix with the size, say, (1m, 10). However, I still don't know how to make the code that much flexible being able to do the matching for a 1 x 3 up to 1 x 10 matchingRow vector.

Sign in to comment.

Accepted Answer

Amir
Amir on 23 Apr 2014
Edited: Amir on 23 Apr 2014
Here's the solution:
rowsMatched = find(all(bsxfun(@eq, bigMatrix, matchingRow),2))

More Answers (1)

Matt Kindig
Matt Kindig on 23 Apr 2014
How about this approach? Is it fast enough?
%bigMatrix is MxN, matchingRow is 1xN
rowsMatched = find(ismember( bigMatrix(:,1:3), matchingRow, 'rows'));

Categories

Find more on Programming in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!