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Finding a cell in an array
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Hi,
I have a large cell aray called "txt". I am looking for a cell that is in this array, but the location/name changes from time to time. But this cell is always located next to one that has "vehicle" in it. How do i go through the text array and find the "vehicle" cell, but index it so I actually grab the cell next to it since that is the one that I want?
Thanks
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Answers (3)
dpb
on 8 Apr 2014
One way...should be a simpler one but it didn't come to me otomh just now...
c is a cell array around had for an earlier query; just added the word 'vehicle' inside the first location...
>> c
c =
'This is vehicle' 'Description 1234567890'
>> find(cellfun(@(x) ~isempty(strfind(x,'vehicle')),c))+1
ans =
2
>> c(find(cellfun(@(x) ~isempty(strfind(x,'vehicle')),c))+1)
ans =
'Description 1234567890'
>>
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Dishant Arora
on 8 Apr 2014
idx = find(cellfun(@(x) isequal(x , 'vehicle') , testCell))+1;
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dpb
on 8 Apr 2014
Ayup...just pointing out the "why" of choosing the apparently more difficult route.
Image Analyst
on 8 Apr 2014
Edited: Image Analyst
on 8 Apr 2014
Try ismember:
txt = {'aaa', 10; 'bbb', 20; 'vehicle', 30; 'ddd', 40}
% Find 'vehicle' in the first column of the above list of strings.
index = find(ismember(txt(:,1), 'vehicle'))
numberYouWant = txt(index, 2) % Extract second column in that row.
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