How can I create a .mat file in which I store the colour images and the corresponding histograms?

I want to create the .mat file in which I need to store the Colour images and corresponding each colour image I need to store 4 histograms in row form. Can any one help me with code how to store color image and corresponding histogram in row form?

[radha]

Thanks in advance!!!!

Answer 1

[Image Analyst]

Make a 2D array of 1024 column by 50 rows

output = zeros(totalNumberOfImages, 1024); % Initialize
for imageNumber = 1 : totalNumberOfImages
  % Compute the 4 histograms...
  % Now save them
  output(imageNumber, :) = [count1, count2, count3, count4];
end

do for all images, then save output (or whatever you want to call it) to a mat file

save(matFullFileName, 'output');

[radha]

I have tried your code but I am getting error. So tell me where I went wrong. I want to also store the color image along with 4 histograms. So tell me how to do that? Currently for checking I have Used 5 as the count instead 50. The code is as below:

output = zeros(5, 1024); % Initialize

for imageNumber = 1 : 5

% Compute the 4 histograms...

Image=imread(strcat('Temp\',num2str(imageNumber),'.jpg'));
Image=imresize(Image,[256 256]);
count1=LRBP(1,Image); %1st Histogram
count2=LRBP(4,Image); %2nd Histogram
count3=LRBP(16,Image); %3rd Histogram
count4=LRBP(64,Image); %4th Histogram
% Now save them
output(imageNumber, :) = [Image,count1, count2, count3, count4];
end

save('Hmat.mat', 'output');

Error is as follow:

??? Subscripted assignment dimension mismatch.

Error in ==> Hist_mat_t1 at 11 output(imageNumber, :) = [count1, count2, count3, count4];

??? Subscripted assignment dimension mismatch.

Error in ==> Hist_mat_t1 at 13 output(imageNumber, :) = [count1, count2, count3, count4];

??? Error using ==> horzcat CAT arguments dimensions are not consistent.

Error in ==> Hist_mat_t1 at 13 output(imageNumber, :) = [Image,count1, count2, count3, count4];

[radha]

Sorry but I am not getting this point: How in .matfile all images and 4 histograms will be saved since we are creating it after the for loop, so it will store the image and histograms of the last image in .matfile??? I mean while running entire for loop all computation will be performed but only single image and its 4 histograms will be saved in .mat file. So please explain me this. Please help me for understanding this.

Thanks a loot!! Image Analyst please resolve my error.

[Image Analyst]

You stuck image at the front, which is a 256x256 array. You can't stitch it horizontally with a 5x1024 array because the numbers of rows don't match. Why do you want to store the image in the mat file anyway? If you did, you'd have to do Image(:) to get it into a row vector, but I don't recommend it since you already have the images stored on disk. If you want you can store the filenames in the same mat file with a different variable name.

[radha]

I will accept the answer once i will get my error resolved... Please reply. I am waiting for your response, Because you have answered my answer till this so i have hope of getting my work done. Thank you very much.................................................!!!!!!!!!!

[Image Analyst]

Just don't save the images, like I said. I'll be in a meeting with the Mathworks people for the next 2 hours so I won't reply until after that.

[radha]

Sorry!! I just Cleared my doubt today. So i don't need to store image in .matfile. It was my misunderstanding. But tell me what should I do to resolve the error which i told you yesterday. How should I modified your code so that i won't get that sunscripted dimension mismatch error. Thanks for your response. I was online when I commented yesterday your comments delivered late. Thanks!!! Please guide me.

[radha]

And I want to understand that we are saving output in .matfile at the end of the for loop so in .matfile there will be only last 4 histograms of image will be there?? This is what i interpreting from your code. So please clear my this doubt how 4 histograms of all images will be stored in .matfile. Please help!! I don't have much knowledge of matlab so i m asking. Thanks in advance!!!

[Image Analyst]

Why do you say that? Notice that output has totalNumberOfImages rows, so every row in the matrix is 1024 elements long, which is the 4 histograms. So you will have every image's histograms in there, not just the last one.

You will not have that error anymore if, like I recommended, you do not try to save "Image" in the row.

[radha]

Image Analyst still I am getting this error. I don't know why? ??? Subscripted assignment dimension mismatch.

Error in ==> Hist_mat_t1 at 12 output(imageNumber, :) = [count1, count2, count3, count4];

Check and tell me where I should make change??

output = zeros(5, 1024); % Initialize for imageNumber = 1 : 5

% Compute the 4 histograms...
Image=imread(strcat('Temp\',num2str(imageNumber),'.jpg'));
count1=LRBP(1,Image); %1st Histogram
count2=LRBP(4,Image); %2nd Histogram
count3=LRBP(16,Image); %3rd Histogram
count4=LRBP(64,Image); %4th Histogram
% Now save them
output(imageNumber, :) = [count1, count2, count3, count4];
end

save('Hmat.mat', 'output');

Image is being resized into 256X256 by the function LRBP which returns the histogram. Guide me. Thanks for response!!!!!

[Image Analyst]

You might need to transpose the counts. Here, try this code:

%----------------------------------------------------------
% Program to read in all the images in a folder and 
% display the histograms.
%----------------------------------------------------------
clc;  % Clear command window.
close all;  % Close all figure windows except those created by imtool.
workspace;  % Make sure the workspace panel is showing.
fontSize = 16;

% Read in standard MATLAB color demo images.
% Construct the folder name where the demo images live.
imagesFolder = fullfile(matlabroot, '\toolbox\images\imdemos');
if ~exist(imagesFolder, 'dir')
  % That folder didn't exist.  Ask user to specify folder.
   message = sprintf('Please browse to your image folder');
  button = questdlg(message, 'Specify Folder', 'OK', 'Cancel', 'OK');
  drawnow;  % Refresh screen to get rid of dialog box remnants.
  if strcmpi(button, 'Cancel')
     return;
  else
    imagesFolder = uigetdir();
    if imagesFolder == 0
      % Exit if uer clicked Cancel.
      return;
    end
  end
end

% Read the directory to get a list of images.
filePattern = [imagesFolder, '\*.jpg'];
jpegFiles = dir(filePattern);
filePattern = [imagesFolder, '\*.tif'];
tifFiles = dir(filePattern);
filePattern = [imagesFolder, '\*.png'];
pngFiles = dir(filePattern);
filePattern = [imagesFolder, '\*.bmp'];
bmpFiles = dir(filePattern);
% Add more extensions if you need to.
imageFiles = [jpegFiles; tifFiles; pngFiles; bmpFiles];

% Bail out if there aren't any images in that folder.
numberOfImagesProcessed = 0;
numberOfImagesToProcess = length(imageFiles);
if numberOfImagesToProcess <= 0
   message = sprintf('I did not find any JPG, TIF, PNG, or BMP images in the folder\n%s\nClick OK to Exit.', imagesFolder);
  uiwait(msgbox(message));
  return;
end

% Create a figure for our images.
figure;
set(gcf, 'Position', get(0,'Screensize')); % Maximize figure.
set(gcf,'name','Image Analysis Demo','numbertitle','off') 

% Initialize array to hold the 4 histograms for all images.
output = zeros(numberOfImagesToProcess, 1024); 
% Loop though all images, calculating and displaying the histograms.
% and stitching them together.
for k = 1 : numberOfImagesToProcess
  % Read in this one file.
  baseFileName = imageFiles(k).name;
  fullFileName = fullfile(imagesFolder, baseFileName);
  grayImage = imread(fullFileName);

  % If we get to here, it's a true color image.
  subplot(1, 2, 1);
  imshow(grayImage, []);
  [rows, columns, numberOfColorBands] = size(grayImage);
  if numberOfColorBands > 1
    % It's not really gray scale like we expected - it's color.
    % Convert it to gray scale by taking only the green channel.
    grayImage = grayImage(:, :, 2); % Take green channel.
  end
  % Create a title for the image.
  caption = sprintf('Original Color Image\n%s\n%d rows by %d columns by %d color channels', ...
    baseFileName, rows, columns, numberOfColorBands);
  % If there are underlines in the name, title() converts the next character to a subscript.
  % To avoid this, replace underlines by spaces.
  caption = strrep(caption, '_', ' ');
  title(caption, 'FontSize', fontSize);
  drawnow;  % Force it to update, otherwise it waits until after the conversion to double.
  subplot(1, 2, 2);
  
  
  % Let's compute and display the histogram.
  [pixelCount, grayLevels] = imhist(grayImage);
  subplot(1, 2, 2); 
  bar(grayLevels, pixelCount);
  grid on;
  title('Histogram of original image', 'FontSize', fontSize);
  xlim([0 grayLevels(end)]); % Scale x axis manually.
  
  % Get the histogram of the 4 quadrants.
  midRow = floor(rows/2);
  midCol = floor(columns/2);
  quadrant1 = grayImage(1:midRow, 1:midCol);
  quadrant2 = grayImage(1:midRow, midCol+1:end);
  quadrant3 = grayImage(midRow+1:end, 1:midCol);
  quadrant4 = grayImage(midRow+1:end, midCol+1:end);
  
  % Let's compute the 4 histograms.
  [pixelCount1, grayLevels1] = imhist(quadrant1);
  [pixelCount2, grayLevels2] = imhist(quadrant2);
  [pixelCount3, grayLevels3] = imhist(quadrant3);
  [pixelCount4, grayLevels4] = imhist(quadrant4);
  
  % Stitch together and stick into one row of the array.
  output(k,:) = [pixelCount1', pixelCount2', pixelCount3', pixelCount4'];
  
  % Prompt user to continue, unless they're at the last image.
  if k < numberOfImagesToProcess
    promptMessage = sprintf('Currently displaying image #%d of a possible %d:\n%s\n\nDo you want to\nContinue processing, or\nCancel processing?',...
      numberOfImagesProcessed, numberOfImagesToProcess, baseFileName);
    button = questdlg(promptMessage, 'Continue?', 'Continue', 'Cancel', 'Continue');
    if strcmp(button, 'Cancel')
      break;
    end
  end
end
save('AllHistograms.mat', 'output');

[radha]

I ran your code it is working fine. According I changed your previous code and tried to run it but now it is giving me error for the function LRBP which returns the histogram. The modified code is:

clc; clear all;

output = zeros(5, 1024); % Initialize

for k = 1 : 5

% Compute the 4 histograms...

Image=imread(strcat('Temp\',num2str(k),'.jpg'));
  [pixelCount1, grayLevels1] = LRBP(1,Image);
  [pixelCount2, grayLevels2] = LRBP(4,Image);
  [pixelCount3, grayLevels3] = LRBP(16,Image);
  [pixelCount4, grayLevels4] = LRBP(64,Image);
  
  % Stitch together and stick into one row of the array.
  output(k,:) = [pixelCount1', pixelCount2', pixelCount3', pixelCount4'];

end

save('Hmt.mat', 'output');

Error is as follows:

??? Error using ==> LRBP Too many output arguments.

Error in ==> ImT at 8 [pixelCount1, grayLevels1] = LRBP(1,Image);

Since LRBP is LBP on radon transform so I am applying radon transform on each block of the divided image then applying LBP on each block so corresponding to each block I have the histogram and I am merging this histograms by your code for that and getting final histogram. So LBBP is that histogram (After concatenating). I am displaying the Output of the LRBP as follow (All 4 Histogram output)

HP0 Columns 1 through 6

        6545         111         320         524       18108        2543

Columns 7 through 12

        3838         265        2556        1352        2242         103

Columns 13 through 18

         470        3913        2404        1380         261         465

Columns 19 through 24

       16803      154179        4381        2827       18119        2557

Columns 25 through 30

        3921      154374       16694         440         252         319

Columns 31 through 36

         526       19479      164429        4241        2761       15377

Columns 37 through 42

        2549        3835      164116       19261         541         334

Columns 43 through 48

        1357        2250        4231         531          60        2396

Columns 49 through 54

        1383        2766         336        4396        2842       15384

Columns 55 through 59

         434         252          67      266472       12799

HP1 Columns 1 through 6

        5766         270         456         809       10294        2770

Columns 7 through 12

        5486         379        2715        2516        6567         202

Columns 13 through 18

         761        5696        7543        2908         381         770

Columns 19 through 24

       18712      157844        6537        2566       10294        2714

Columns 25 through 30

        5722      157983       18377         724         393         448

Columns 31 through 36

         805       20762      153522        6158        2874        7580

Columns 37 through 42

        2764        5477      153369       20405         843         532

Columns 43 through 48

        2516        6553        6115         842         212        7582

Columns 49 through 54

        2930        2863         526        6566        2567        7620

Columns 55 through 59

         726         395         191      270377       10781

HP2 Columns 1 through 6

       14345         753        1357        2688       15469        6229

Columns 7 through 12

       18696        1241        6074       10153       53354         718

Columns 13 through 18

        2694       19061       55329       12662        1243        2696

Columns 19 through 24

       41412      341309       22786        5810       15475        6060

Columns 25 through 30

       19042      341332       40599        2604        1291        1349

Columns 31 through 36

        2677       42217      336512       22330        6033        9051

Columns 37 through 42

        6206       18692      336528       41578        2686        1333

Columns 43 through 48

       10130       53304       22295        2684         784       55376

Columns 49 through 54

       12701        6003        1313       22761        5802        9024

Columns 55 through 59

        2618        1296         820      645945       25360

HP3 Columns 1 through 6

       30102        5085        3555        9899       15312       10839

Columns 7 through 12

       56317        3325        9843       30269      276993        5140

Columns 13 through 18

        9330       52878      280861       37572        3339        9358

Columns 19 through 24

       87419      657504       63104        6715       15320        9842

Columns 25 through 30

       52869      657527       85750        8151        2718        3541

Columns 31 through 36

        9897       91631      666777       66487        7780        5495

Columns 37 through 42

       10836       56282      666817       89944        8631        2813

Columns 43 through 48

       30260      277076       66507        8648        5273      280846

Columns 49 through 54

       37589        7777        2813       63122        6720        5492

Columns 55 through 59

        8166        2704        5110     1307816       49847

>> SO Now what should I do??? since I am getting output of LRBP histograms as above. I tried using imhist on the LRBP histogram but it makes all the values to zero and only last values has some number. So I can't use imhist.

Thanks Image analyst for your continual support but again im stucked. So please guide me.

Thanks!!!!!!!!!

[Image Analyst]

Put the cursor in LRBP and type control-d and tell me what the function line says. It might look something like

function [out1, out2] = LRBP(input1, input2)

but it probably looks like

function out1 = LRBP(input1, input2)

and provides only 1 output but you are expecting it to provide 2 outputs.

[radha]

Means I should type control-d in command prompt after putting cursor in LRBP function???

[radha]

I m not getting where to type control-d. I tried on command prompt but it gives me error. No such variable. And in the file of the LRBP but nothing happens. So please explain how to do that so that I can check what you want and let you know.

WE can proceed further.

[radha]

Sorry I asking Many questions but I m not getting it. Please reply. you have done lot for me.

Thanks a lot!!!!

Please fix this. This is last part of my project. Waiting for your Reply.....

[Image Analyst]

Put the cursor right over the word "LRBP" in your text editor, then click. You will get a veritical blinking cursor between some letters of that word. Then type control-D or right click and select Open LRBP from the pop up context menu. It should bring you to LBRP source code. Then tell me how it's defined.

[radha]

LRBP function I have created and defined. It takes the number of blocks as first input and image as second input. Then based on number of blocks given it divides the image into that number of blocks and apply radon transform on each block then lbp on that radon transform. Thus Each block has histogram which is then merged into single histogram. Basically I am using spatial pyramid with level 4 so level one has one grid i.e. entire Image, level 2 has 4 blocks, level 3 has 16 blocks, level 4 has 64 blocks. So there are 4 cases in LRBP ie. no_of_blocks = 1,4,16,64. thus corresponding to these 4 level I m storing these histogram(i.e. after merging histograms of all blocks) in .matfile. Hence 4 histograms. Source code is here:

function Hist = LRBP( no_of_block,Image )

%UNTITLED33 Summary of this function goes here

% Detailed explanation goes here

theta=0:360;

mapping=getmapping(8,'u2');

Image=imresize(Image,[256 256]);

%imshow(Image),figure;

[rows columns numberOfColorBands] =size(Image);

%64 Blocks

if no_of_block==64

blockSizeR = 35; % Rows in block.

blockSizeC = 35; % Columns in block.

wholeBlockRows = floor(rows / blockSizeR);

blockVectorR = [blockSizeR * ones(1, wholeBlockRows), rem(rows, blockSizeR)];

wholeBlockCols = floor(columns / blockSizeC);

blockVectorC = [blockSizeC * ones(1, wholeBlockCols), rem(columns, blockSizeC)];

if numberOfColorBands > 1

ca = mat2cell(Image, blockVectorR, blockVectorC, numberOfColorBands);

else

ca = mat2cell(Image, blockVectorR, blockVectorC);

end

plotIndex = 1;

numPlotsR = size(ca, 1);

numPlotsC = size(ca, 2);

for r = 1 : numPlotsR

for c = 1 : numPlotsC

%fprintf('plotindex = %d, c=%d, r=%d\n', plotIndex, c, r);

% Specify the location for display of the image.

%subplot(numPlotsR, numPlotsC, plotIndex);

% Extract the numerical array out of the cell

%Block = ca{r,c};

%imshow(Block); % Could call imshow(ca{r,c})

%[rowsB columnsB] = size(Block);

% Make the caption the block number.

%caption = sprintf('Block #%d of %d\n%d rows by %d columns', ... % plotIndex, numPlotsR*numPlotsC, rowsB, columnsB); %title(caption); %drawnow; % Increment the subplot to the next location.

plotIndex = plotIndex + 1;

end

end

%disp(ca);

%subplot(4, 6, 1);

%imshow(Image),figure;

%title('Original Image');

sumHist =lbp(radon(double(ca{1,1}),theta),1,8,mapping,'h');

    for i=2:r

        for j=2:c

            sumHist=sumHist+lbp(radon(double(ca{i,j}),theta),1,8,mapping,'h');

        end

    end

    Hist=sumHist;

end

%16 Blocks if no_of_block==16

 blockSizeR = 70; % Rows in block.
blockSizeC = 70; % Columns in block.
wholeBlockRows = floor(rows / blockSizeR);
blockVectorR = [blockSizeR * ones(1, wholeBlockRows), rem(rows, blockSizeR)];
wholeBlockCols = floor(columns / blockSizeC);
blockVectorC = [blockSizeC * ones(1, wholeBlockCols), rem(columns, blockSizeC)];

if numberOfColorBands > 1 ca = mat2cell(Image, blockVectorR, blockVectorC, numberOfColorBands); else ca = mat2cell(Image, blockVectorR, blockVectorC); end

plotIndex = 1; numPlotsR = size(ca, 1); numPlotsC = size(ca, 2);

for r = 1 : numPlotsR for c = 1 : numPlotsC %fprintf('plotindex = %d, c=%d, r=%d\n', plotIndex, c, r); % Specify the location for display of the image. %subplot(numPlotsR, numPlotsC, plotIndex); % Extract the numerical array out of the cell %Block = ca{r,c}; %imshow(Block); % Could call imshow(ca{r,c}) %[rowsB columnsB] = size(Block); % Make the caption the block number. %caption = sprintf('Block #%d of %d\n%d rows by %d columns', ... % plotIndex, numPlotsR*numPlotsC, rowsB, columnsB); %title(caption); %drawnow; % Increment the subplot to the next location. plotIndex = plotIndex + 1; end end %disp(ca); %subplot(4, 6, 1); %imshow(Image),figure; %title('Original Image');

sumHist =lbp(radon(double(ca{1,1}),theta),1,8,mapping,'h');

    for i=2:r
        for j=2:c
            sumHist=sumHist+lbp(radon(double(ca{i,j}),theta),1,8,mapping,'h');
        end
    end

    Hist=sumHist;

end

%4 Blocks if no_of_block==4

 blockSizeR = 200; % Rows in block.
blockSizeC = 200; % Columns in block.
wholeBlockRows = floor(rows / blockSizeR);
blockVectorR = [blockSizeR * ones(1, wholeBlockRows), rem(rows, blockSizeR)];
wholeBlockCols = floor(columns / blockSizeC);
blockVectorC = [blockSizeC * ones(1, wholeBlockCols), rem(columns, blockSizeC)];

if numberOfColorBands > 1 ca = mat2cell(Image, blockVectorR, blockVectorC, numberOfColorBands); else ca = mat2cell(Image, blockVectorR, blockVectorC); end

plotIndex = 1; numPlotsR = size(ca, 1); numPlotsC = size(ca, 2);

for r = 1 : numPlotsR for c = 1 : numPlotsC %fprintf('plotindex = %d, c=%d, r=%d\n', plotIndex, c, r); % Specify the location for display of the image. %subplot(numPlotsR, numPlotsC, plotIndex); % Extract the numerical array out of the cell %Block = ca{r,c}; %imshow(Block); % Could call imshow(ca{r,c}) %[rowsB columnsB] = size(Block); % Make the caption the block number. %caption = sprintf('Block #%d of %d\n%d rows by %d columns', ... % plotIndex, numPlotsR*numPlotsC, rowsB, columnsB); %title(caption); %drawnow; % Increment the subplot to the next location. plotIndex = plotIndex + 1; end end %disp(ca); %subplot(4, 6, 1); %imshow(Image),figure; %title('Original Image');

sumHist =lbp(radon(double(ca{1,1}),theta),1,8,mapping,'h');

    for i=2:r
        for j=2:c
            sumHist=sumHist+lbp(radon(double(ca{i,j}),theta),1,8,mapping,'h');
        end
    end

    Hist=sumHist;

end

if no_of_block==1 Hist=lbp(radon(double(Image),theta),1,8,mapping,'h'); end

end

[radha]

I am implementing LRBP algorithm. So I declared function instead of copy pasting the code for each level of spatial pyramid for getting the merged histogram. So Now You say what went wrong. For dividing image into blocks code I have taken form matlab central only.

Thanks a lot for your support. Guide me. Thanks!!!!

[Image Analyst]

Look how you defined it:

function Hist = LRBP( no_of_block,Image )

Notice there is only one single output . Now, look how you're calling it:

 [pixelCount1, grayLevels1] = LRBP(1,Image);

You're expecting two outputs , not one! So what's called Hist inside LRBP gets assigned to pixelCount1 in the main program, but LRBP does not pass back any second argument so there is nothing to stuff into grayLevels1 . That's why it says there are too many output arguments. If you want grayLevels1, you need to pass something out that can be put into grayLevels1.

[radha]

So what should I put there in grayLevels1??? OR I change it like this???

[pixelCount1]=LRBP(1,Image);

But this will have any impact on the output?? Sir, you suggest what should I do???

[Image Analyst]

Just don't accept grayLevels. Or send it out. Either way. You don't need it in your calling code so I'd just leave it off when you call it.

pixelCount1 = LRBP(1,Image);

[radha]

Sir, I tried using

[pixelCount1]=LRBP(1,Image);

But I am getting error of

??? Subscripted assignment dimension mismatch.

Error in ==> ImN at 14 output(k,:) = [pixelCount1', pixelCount2', pixelCount3', pixelCount4'];

So I need to pass something there in the grayLevels1.

So How I will get grayLevels1 value?? Guide me sir.

Thanks a Lott!!!! Guide.

[Image Analyst]

You need to step though this in the debugger. Are all PixelCountn 1024 rows by 1 column wide arrays? If they're 1x1024 instead of 1024x1 then get rid of the transpose ' operator. What are the sizes of them? What is the value of k? Just go through the normal debugging steps.

[radha]

Sir, I checked in workspace the values of pixelCounts these are of the size 1X59 so I removed transpose operator but it is giving again the same error.

??? Subscripted assignment dimension mismatch.

Error in ==> ImN at 14 output(k,:) = [pixelCount1, pixelCount2, pixelCount3, pixelCount4

];

[radha]

Value of k is one. Sorry sir, again stuck up.

Thanks for support.

Guide me.

[radha]

Code is:

clc;

clear all;

output = zeros(5, 1024); % Initialize

for k = 1 : 5

% Compute the 4 histograms...
Image=imread(strcat('Temp\',num2str(k),'.jpg'));
  pixelCount1 = LRBP(1,Image);
  pixelCount2 = LRBP(4,Image);
  pixelCount3 = LRBP(16,Image);
  pixelCount4 = LRBP(64,Image);
  
  % Stitch together and stick into one row of the array.
  output(k,:) = [pixelCount1, pixelCount2, pixelCount3, pixelCount4];

end

save('Hmtt.mat', 'output');

[radha]

Image Analyst what should I do now?? How can I get the value of grayLevels1 in LRBP??? Since As I told you the above code is giving me error of subscripted dimension mismatch at the line below.....

??? Subscripted assignment dimension mismatch.

Error in ==> ImN at 14 output(k,:) = [pixelCount1, pixelCount2, pixelCount3, pixelCount4

though I removed transpose operator.

Please help me.

Thanks a lot!!!! But I don't know how to deal with this now. Why subscripted dimension ??

Else How should I modify LRBP so as it return two outputs...

Please help me to finish this work of .matfile.

Thanks in advance!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[radha]

Image Analyst I have tried by using grayLevles as output with the value = 59 in LRBP since 59 is total number of values in each LRBP histogram. code is:

clc;

clear all;

output = zeros(5, 1024); % Initialize

for k = 1 : 5

% Compute the 4 histograms...
Image=imread(strcat('Temp\',num2str(k),'.jpg'));
  [pixelCount1, grayLevels1] = LRBP(1,Image);
  [pixelCount2, grayLevels2] = LRBP(4,Image);
  [pixelCount3, grayLevels3] = LRBP(16,Image);
  [pixelCount4, grayLevels4] = LRBP(64,Image);
  
  % Stitch together and stick into one row of the array.
  output(k,:) = [pixelCount1, pixelCount2, pixelCount3, pixelCount4];

end

save('H.mat', 'output');

??? Subscripted assignment dimension mismatch.

Error in ==> ImLast at 14 output(k,:) = [pixelCount1, pixelCount2, pixelCount3, pixelCount4];

Still I am getting the subscripted assignment mismatch error.

So sir, please guide how I should resolve this subscripted dimension mismatch error. Why subscripted dimension error is coming every time I run??

Please solve this error. Thanks sir!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Thanks a lot!!!! Help me this last point of .matFile.

[radha]

I will accept your answer please solve this error. I am waiting for your response.... Please help...............

Thanks!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[radha]

Please Answer me!!!!

[radha]

Image Analyst Please!!!! I want to complete my project!!!

[radha]

Image Analyst I have understood now why I am getting subscripted dimension mismatch error.

Can you noe just help me to resolve small thing.

In case of imhist in your program working fine because the pixelCounts for them are displayed in this form. Given below....

1

2

3

4

5

 like this.

And in case of LRBP pixelCounts are displayed like this:

columns 1 to 7

1 2 3 4 5

I this form.

That's Why I am getting subscripted dimension mismatch as error. This what I tried to find out cause of the error.

Now can you please help me to guide what should I change??

So that This error will be resolved.

[radha]

Can you just tell me how to change pixelCounts display and saving method of the LRBP to be displayed and stored like imhist.

Then error will be resolved.

[radha]

I am on the way of completion.

Please help.

Thanks!!! Please reply I am in tension.

Please..............................................

[Image Analyst]

Can you attach any m-files and data needed to run your program? I might be able to get to it this afternoon.

[radha]

yes sir!!! Sure.

I am attaching all the files needed to run my program. If you want then I can also send ppt of LRBP algorithm as well.

Thanks a lott.!!!!!! I am really thankful to you!!!!!

[radha]

First I am attaching the LRBP then lbp and getmapping..

Then attaching the demo file for single image matching. I have to get the input sketch image by user then get LRBP histogram at each level and compare these sketch image histograms with the LRBP histograms of color image at each level stored in .matfile.

But currently since .matfile is not created so I n demo matching is performed with respect to single image. If match is found then display message saying person present in database otherwise not present. PMK is distance used for comparing the LRBP histograms at each level.

I am using CUHK database for sketch images and corresponding photo images for this project. Basically it is used when eye-witness is only proof. So sketch will be drawn by artist and it is given as input to my project then there is criminal database having the face photo which is used for matching sketch with photo if match found the disply that message if not then that message. For this I am implanting LRBP algorithm.

[radha]

Images for sketch and photo are inserting here. Iam insering 5 isketch images and 5 photo images.

[radha]

Images are not being uploaded because it is giving me error !!!

No more then 10 file upload..

Wait for 24 hours.

So I am not able to send you th sketch and photo images.

[Image Analyst]

If it's going to be a ton of work then I won't be able to help. I'm expecting like 5 minutes or less to find the error and fix it. If it gets more involved than that then I will just have to pass. You can zip your files together into a single zip file.

[radha]

Okay. I will zip and send you.

Sir I explained indetail so that you have idea of what I am doing.

All these files are needed for running the .matile code.

So I am attaching with the your code of .matfile which I stored in .m file along with all other files.

Thanks for your help!!! I hope my error will be resolved.!!!

Thanks a lot!!!!!!!!!!!!!!!!!!!!!!

[radha]

Sir you only have to resolve my subscripted dimension error. Rest thing I know how to do it.

Sir the file name ImLast is the file where your code of the .matfile is there. To run this you will need three files LRBP,lbp and getmapping.No need to have PMK.

Sir just resolve my .matfile error in the file ImLast.m

Thanks A LOOTTT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[radha]

Sory sir I am unable to upload the .zip file because of error.

[radha]

I is saying remove one or more files. So removed previously attached files.

Still not able to upload..

Error

[radha]

Now uploaded successfully.........................

Sir Now as i explained you can use the file Imlast.m which in turn uses the LRBP,lbp and getmapping files. You here just need to use photo images only. So You can use any photo image.

Thanks a lot!!!!!!!!!!!!!!!!

[radha]

Sir you just have to solve subscripted dimension mismatch error only.

No other work...

So I don't think it will take more time.

Thanks for contributing your time with me..

Thanks a Lot!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[radha]

Sir, will you now solve this and reply me the solution???

Because for this error I am totally dependent on you, since I have tried at my level best and no other helping me.

Please give me some positive response.

Thanks!!!!

Please reply me whatever you perform for this. So I can decide what should I do???

[radha]

Sir, my intension is not to get every thing done by you. I have done 80% work. Only this last 20% work of .matfile is remaining.

So please just solve .matFile error.

Thanks!!!!!

Please give me response whether you are going to do or you don't have time.

Please reply. I am waiting sir........................

Thanks a lot!!!!!!!!!!!

[Image Analyst]

Probably not until tomorrow night. If you solve it yourself earlier let me know so I don't waste my time.

[radha]

Okay, sure sir....

I am trying my best....

Let see...

I will tell you if and only if I will succeed in solving it.

Otherwise you will have to help.

Thanks!!!!

[radha]

Sir, can you just tell me whether we can store large values in the array created using zero. such large like 29366.

Because I thought due to this I am getting subscripted dimension mismatch. so

Just tell me can we store such large values in array of output created using zero????????????

Thanks!!!!!!!!!!!!!!!

[Image Analyst]

Yes you can.

[radha]

Sir I tried you clear first thing Whether pixelCounts1 and pixelCounts2, etc.. It should have single value or it should be array.

Because I think if it should be single value then I am getting dimension mismatch error, since pixelCounts1,pixelCounts2, etc are returning 1X59 arry.

[radha]

Sir I tried small script as below..

clc;

clear all;

out=zeros(5,1024);

for i=1:5

    out(i,:)=[1 2 3 4];
end
save('T.mat','out');

But for this I am also getting the dimension mismatch error. So how to solve this for small code.

I think there is error in the code.

what do you think sir????

Can we achieve the our aim for storing in row form .matfile with this code??? For imhist it is working fine. But why not for LRBP????

Please help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Thank you sir!!!!!!!!!!!!!

[radha]

Shall we able to solve this error???

Sir I tried but not able to solve.

I need to finish by this Friday.

So if we can't solve this then there is any other alternate way to store in row wise form.

If yes then tell me I will try that....

I tried a lot sir because deadline is near...

I have to complete this...

So please guide me....

thanks for your continual response!!!!!!

Thanks a lot!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[Image Analyst]

In out(i,:)=[1 2 3 4]; the right hand side needs to be 1024 elements long, not 4. If you have 4 histograms of 256 elements each, then it will be 1024 elements long.

[radha]

Exactly I had not changed that 1024 that is why I was getting error. Because my histograms has only 59 values. So not getting done my .matfile.

Now it's working fine.

Sir I am bit late to share my happiness because I was running my entire project.

It is good news for me that I have completed my project. I am very happy.

I don't know how much to say thanks to you. Without your help of my project would not be completed within deadline.

Sorry I disturbed you lot....

But Thanks a Lottttttttttt Image Analyst!!!!!!!!!!!!!!

Now I am developing GUI.

Thanks again....

You played very important role for my project. I never forget your help. Because only this .matfile work was left and you helped me to do that.

Again Thanks a Loootttt!!!!!