How to use parfor for fast matrix calculations with different dimensions???

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Mandar on 26 Feb 2014
Answered: Mandar on 26 Feb 2014
Here is the code that i wrote to find 1 in the matrix with general for-loop:
b=[0 0 0 0 0 0 0 0 0 0; 0 0 0 0 0 0 0 0 0 0; 0 0 0 1 1 0 0 0 0 0; 0 0 1 1 1 1 1 0 0 0; 0 0 0 1 1 1 0 0 0 0; 0 0 0 1 1 0 0 0 0 0; 0 0 0 0 0 0 0 0 0 0; 0 0 0 0 0 0 0 0 0 0]; n=0; s=size(b,1); %rows t=size(b,2); %columns v = zeros(s*t,2); for g=1:s for h=1:t if b(g,h)== 1 n=n+1; v(n,:)=[g h;]; end end end v v=(v(v~=0))
here are 2 problems:
a) i can't use the counter 'n', so i made a formula n=col+(row-1)*col. However parfor doesn't allow me to use the index from the earlier loop :O :( please tell me how should i use the parfor to search position of the 1!!! :(
b) i want the final v matrix without zero i.e. with the values other than 0 only. v=(v(v~=0)) works and gives the v matrix in a column matrix. that is not what i want. :(

Thomas on 26 Feb 2014
Edited: Thomas on 26 Feb 2014
You do not need to use 'parfor' or even 'for' to get to what you are trying (i.e. find 1's in the matrix). Is there a specific requirement to use 'parfor' or 'for'?
this single line of code does everything your code does and I'm sure is faster than a parfor..
[row,col]=find(b==1);
out=[row col] % is you want it as a matrix
If you definitely want to use parfor try reading the Reduction Assignments: http://www.mathworks.com/help/distcomp/getting-started-with-parfor.html#brdqn6p-1

Mandar on 26 Feb 2014
Actually i have wrote down something like this to search for a color reference in live feed from webcam:
opengl hardware while (nFrame<z)
b = step(vidobj);
n=0;
yb=size(b,1); %rows
zb=size(b,2); %columns
%u=zeros(zb,2); %------------------------------
v=0;
for g=1:1:yb
for h=1:1:zb
if (b(g,h,1)>=rot_min) && (b(g,h,1)<=rot_max)
n=n+1;
v(n,1)=g;
v(n,2)=h;
end
end
end
v;
%end of rot search
so now i want to exploit the core i5 to use all for cores and make the code even more faster...