Creating a matrix with values that increase cyclically
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John Moseley
on 28 Dec 2013
Commented: John Moseley
on 29 Dec 2013
Hello,
I would like to create a matrix with two columns. The rows 1-670 would be 1,1; rows 671-1340 rows would be 1,2; rows 1341-2010 would be 1,3. And this trend would continue through the 670 rows of 1,256. After these rows, the next 670 rows would be 2,1; the next 670 rows would be 2,2; and the next 670 rows would be 2,3. So the trend is that every 670 rows, the second column increases by one. And every 670x256 rows, the first column increases by one and the second column resets at one.
Can someone please help with this? Any hints will be helpful.
Many thanks,
John
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Accepted Answer
Roger Stafford
on 28 Dec 2013
An alternative to that is:
m = 256;
n = 670;
t = (.5:m^2*n-.5)'/n;
M = [floor(t/m),mod(floor(t),m)]+1;
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Roger Stafford
on 28 Dec 2013
m1 = 238;
m2 = 256;
n = 670;
followed by either this:
M = [reshape(repmat(1:m1,n*m2,1),[],1),...
reshape(repmat(repmat(1:m2,n,1),1,m1),[],1)];
or this:
t = (.5:m1*m2*n-.5)'/n;
M = [floor(t/m2),mod(floor(t),m2)]+1;
More Answers (1)
Roger Stafford
on 28 Dec 2013
M = [reshape(repmat(1:256,670*256,1),[],1),...
reshape(repmat(repmat(1:256,670,1),1,256),[],1)];
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