How to Make a function accept vector inputs
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Chuzymatics Chuzymatics
on 21 Dec 2013
Commented: Walter Roberson
on 29 Mar 2017
function Ml = myseries(t)
n=0;
while (n<10)
Ml = sum(t.^n/(gamma(n + 1)));
n = n+1;
end
The above code runs well as long as the input variable is a scalar; for vectorized inputs, it fails. What might be wrong?
4 Comments
Walter Roberson
on 29 Mar 2017
./ would only be needed if the right hand side, gamma(n+1) was a vector or matrix, but in this context it is a scalar.
Accepted Answer
Youssef Khmou
on 21 Dec 2013
You did not specify how the output should be , 1x1 or Nx1 , you can try this way :
function Ml = myseries(t)
n=0;
ctr=1;
while (n<10)
Ml(ctr) = sum(t.^n/(gamma(n + 1)));
n = n+1;
ctr=ctr+1;
end
0 Comments
More Answers (2)
Walter Roberson
on 21 Dec 2013
Your current code overwrites all of Ml each time through the "while" loop, and so is unlikely to be doing what you want.
for n = 0 : 9
Ml(n,:) = sum(t.^n/(gamma(n + 1)));
end
4 Comments
Walter Roberson
on 21 Dec 2013
Right, sorry,
for n = 0 : 9
Ml(n+1,:) = sum(t.^n/(gamma(n + 1)));
end
Image Analyst
on 21 Dec 2013
Edited: Image Analyst
on 21 Dec 2013
I think you can to what you want to do with one of these functions. Not sure what you want to do so pick one:
function theSum = myseries(t)
% Vectorized method.
n = 1:length(t);
theSum = sum(t.^n ./ (gamma(n + 1)));
function theSum = myseries(t)
% For loop method.
theSum = 0;
for n = 1 : length(t)
theSum = theSum + t(n)^n ./ gamma(n + 1);
end
This does something completely different than the other two answers but I think is what you were actually intending, which is trying to sum a series.
5 Comments
Image Analyst
on 23 Dec 2013
Well he accepted your interpretation so I guess you were right. The Ml(2) was the sum of terms 1 and 2, the Ml(3) was the sum of terms 1, 2, and 3, and the element Ml(N) was term1 + term2 + term3 + term4 +....+termN. I thought he wanted just one sum - the sum of terms 1 through term N - not N sums, but I guess I was wrong.
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