Day of year to month
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I have a years worth of data in the form of 1-365 (in a column of my matrix), and I want to change it to the days in a month, so I can plot a graph that is quicker to read, rather than having to work out, what month day 100 etc.. belongs to.
I'm sure it's really easy to do but I'm completely out of my depth.
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Answers (5)
Andreas Goser
on 9 Feb 2011
I am not 100% sure, but maybe this example helps you
d2011=734504; % 734504 ist the first day of 2011 - example
v=d2011:d2011+100; % create a vector of 100 days
datestr(v) % see all the dates as strings - use for the figure
datevec(v) % can extract day of month
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Brett Shoelson
on 9 Feb 2011
If you have 365 days, for instance, but no month information, you can simply increment the DAY position in datenum:
mydates = datenum(2011,1,1:365,h,m,s);
Or, if you want the y,m,d,h,m,s:
[y,m,d,h,m,s] = datevec(datenum(2011,1,1:365,h,m,s))
Cheers,
Brett
3 Comments
Brett Shoelson
on 9 Feb 2011
The answer doesn't change; you can specify the hour in the variable h.
Brett
Brett Shoelson
on 10 Feb 2011
How about this?
D = datevec(datenum(1992,1,1:1/24:365, 0,0,0));
Cheers,
Brett
Walter Roberson
on 10 Feb 2011
I suspect you can skip all of this trouble and use datetick()
2 Comments
Walter Roberson
on 10 Feb 2011
http://www.mathworks.com/help/techdoc/ref/datetick.html
datetick('x','mmm HH')
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