How to plot vectors using quiver3

1 view (last 30 days)
baba
baba on 5 Jul 2011
here is my code i need to plot a,T,B,and N at t=pi on the interval -pi:0.1:pi but i cant get it to work can anybody help me please.
syms t
a=[0.5*cos(t), -sqrt(3)/2*cos(t), 1+sin(t)];
T=diff(a);
Answer1=T
N=diff(T);
Answer2=N
B=simplify(cross(T,N));
Answer3=B
C=cross(T/(sqrt(sum(T.^2)))^3,N/(sqrt(sum(T.^2)))^3);
Answer4=simplify(C)
syms t clear
t=-pi:0.1:pi;
a=[0.5*cos(t), -sqrt(3)/2*cos(t), 1+sin(t)];
T=diff(a);
N=diff(T);
plot3(0.5*cos(t), -sqrt(3)/2*cos(t), 1+sin(t))
hold on
plotT=quiver3(-0.5,0.866025403,0,-sin(pi)/2, (3^(1/2)*sin(pi))/2,
cos(pi))
plotN=quiver3(0,0,-1,-cos(pi)/2, (3^(1/2)*cos(pi))/2, -sin(pi))
plotB=quiver3(pi,pi,pi,-3^(1/2)/2, -1/2, 0)
hold off
  1 Comment
bym
bym on 5 Jul 2011
you said you need to plot at t = pi, yet then you mention interval of -pi:.1:pi can you clarify?

Sign in to comment.

Answers (0)

Categories

Find more on Mathematics in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!