How can I plot multiple signals with unit step signal
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Aous Younis
on 15 Nov 2013
Commented: Aous Younis
on 15 Nov 2013
I need to plot this function:
v(t)=(2t+1)[u(t)-u(t-1)]+3[u(t-1)-u(t-2)]+(-t+3)[u(t-2)-u(t-3)]
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Accepted Answer
Azzi Abdelmalek
on 15 Nov 2013
t=-5:0.1:5
v=(2*t+1).*(heaviside(t)-heaviside(t-1))+3*(heaviside(t-1)-heaviside(t-2))+(-t+3).*(heaviside(t-2)-heaviside(t-3))
plot(t,v,'linewidth',4)
More Answers (1)
Wayne King
on 15 Nov 2013
Edited: Wayne King
on 15 Nov 2013
Looks to me like this just simplifies to:
\delta(t) +3\delta(t-1) + \delta(t-2)
N = 128;
sig = zeros(N,1);
idx = 1:3;
sig(idx) = [1 3 1];
stem(sig)
u(t)-u(t-1) is like the derivative of the unit step at t, which is the delta function (distribution)
You can see it's equal if you implement your equation above using the differences of the translated unit step functions:
stepfunc = ones(128,4);
stepfunc(1,2) = 0;
stepfunc(1:2,3) = 0;
stepfunc(1:3,4) = 0;
t = (0:127)';
v1 = 2*t+1;
v2 = -t+3;
v = v1.*(stepfunc(:,1)-stepfunc(:,2))+ 3*(stepfunc(:,2)-stepfunc(:,3))+...
v2.*(stepfunc(:,3)-stepfunc(:,4));
subplot(211)
stem(v)
subplot(212)
stem(sig)
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