Looping with indices that are not equally spaced
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I'm trying to run a loop on a group of indices I obtained using "find". The indices will not always be consecutive. So, running a for loop like:
won't work. I'm trying to avoid doing something like:
for i = 1:length(VECTOR)
Any ideas?
2 Comments
Oleg Komarov
on 23 Jun 2011
not clear why it won't work. Depends how you structure the operations inside the loop. Post more code.
Daniel Shub
on 23 Jun 2011
What do you mean it doesn't work? What would you expect to get with:
indices = [1,2,3,5,7,13,11];
for i = indices, i, end
Accepted Answer
Laura Proctor
on 23 Jun 2011
Actually, it will work.
for idx = [ 1 -2 10 12.5 0 ]
disp(idx)
end
Isn't MATLAB cool?
0 Comments
More Answers (2)
John F
on 23 Jun 2011
2 Comments
Laura Proctor
on 23 Jun 2011
Edited: Walter Roberson
on 22 Dec 2019
You are correct - check out Loren's Blog, it explains this behavior much better than I can:
Daniel Shub
on 23 Jun 2011
Edited: Walter Roberson
on 22 Dec 2019
Yeah, but check out what it does do with a column. You should have a read of:
Frederick Abangba Akendola
on 22 Dec 2019
Please, how do I write a “For” loop with irregular interval? For example; 2,4,8,16,32
1 Comment
Walter Roberson
on 22 Dec 2019
for K = 2.^(1:5)
result = whatever involving K
end
However, most of the time you want to create one output per input. The general way to do that is
K_vals = 2.^(1:5);
numK = numel(K_vals);
results = zeros(size(K_vals));
for K_idx = 1 : numK
K = K_vals(K_idx);
results(K_id) = whatever involving K
end
plot(K_vals, results)
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