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Raphael Hatami


Last seen: mer än 3 år ago Active since 2019

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plotting: making an array out of values made in a for loop?
Hello, I have variable theta and 100 points along its interval, and have found 100 corresponding points of phi. Now I need to pl...

mer än 4 år ago | 1 answer | 0

1

answer

Answered
finding an array of roots?
Kalyan, thanks for taking the time to do this. I actually realized everything was already working properly and I just was readi...

mer än 4 år ago | 0

Question


finding an array of roots?
Hello, I'm trying to find the root of f with respect to phi, given multiple values of theta. However, when doing this, it calcul...

mer än 4 år ago | 2 answers | 0

2

answers

Question


help plotting basic x vs y?
Hello, I am trying to plot x and y from x = 0 to x=L. Right now it goes haywire and plots a bunch of vertical lines which is not...

mer än 4 år ago | 1 answer | 0

1

answer

Question


Help plotting function with i?
Hello, I am trying to plot x and y from x = 0 to x=L. I was having trouble with it, but line y=funct... seems to have fixed it. ...

mer än 4 år ago | 0 answers | 0

0

answers

Question


use taylor series result to find value?
Hello, I think this is relatively simple but I can't figure it out. I am computing the taylor series of a function and simply wa...

mer än 4 år ago | 2 answers | 0

2

answers

Question


unexpected string scalar error?
Hello, I am trying to do taylor series expansion from 0 order to 3 with base point 1 (and estimating f(3)) for the given equatio...

mer än 4 år ago | 1 answer | 0

1

answer

Question


error: Unable to perform assignment because the left and right sides have a different number of elements.
Hello, bit of a long code here but the error seems to just be in line 33, pipeCost(i) = price1*10 + price2*(pipeLength-10); err...

mer än 4 år ago | 3 answers | 0

3

answers

Question


piecewise function only plotting half?
Hello, I am very new to matlab and am trying to graph a function of mutiple piecewise conditions. However, it only seems to be g...

mer än 4 år ago | 0 answers | 0

0

answers