Community Profile

photo

Matt J


6 137 total contributions since 2009

Professional Interests: medical image processing, optimization algorithms

PLEASE NOTE: I do not read email sent through my author page. Please post questions about FEX submissions in their respective Comments section.

Contact

Matt J's Badges

  • Personal Best Downloads Level 4
  • First Review
  • 5-Star Galaxy Level 5
  • First Submission
  • Master
  • Revival Level 4
  • 36 Month Streak
  • Thankful Level 4
  • Knowledgeable Level 4
  • First Answer

View details...

Contributions in
View by

Answered
integers to English phrase
As a further hint, consider the following version, which is almost what you want function S = convert_to_words(number) ones...

en dag ago | 0

| accepted

Answered
Create an array of handle objects using for-loop
Undoubtedly, you meant to have for i = 1:-0.1:0.9 for j = 1:-0.1:0.9

en dag ago | 0

| accepted

Answered
Optimising Problem - Max Profit
You should be using linprog to solve this problem. It does not require a starting point x0. I don't see any need for equality co...

en dag ago | 0

Answered
How I do evaluate a function handle in other function handle
What you probably have to do is use ode45 or similar to solve the differential equation dy/dx = f(x,y) on some interval. Then, f...

en dag ago | 0

Answered
Extract submatrix from matrix.
>> S=regionprops(yourMatrix>0,'Image'); >> S.Image ans = 2×2 logical array 1 1 1 1 ans = 2×3 lo...

2 dagar ago | 1

Answered
Update graph (Graph Theory)?
Perhaps like this, hold on H = subgraph(G,idx); %new part of graph plot(H,'Layout','force','XData',___, 'YData',_____) ...

2 dagar ago | 0

| accepted

Answered
fit options in a parfor loop
A guess as to why this might be happening is that fitoptions objects don't seem to implement proper save/load behavior, as indic...

2 dagar ago | 2

Answered
Something strange in MATLAB
Chances are the issue is not in the code, but in the new data that you have supplied as input. For some reason, this input data ...

2 dagar ago | 0

Answered
How I do evaluate a function handle in other function handle
I think this line needs to be g=@(x,y) f(x,y)*p_y(f,x,y) + p_x(f,x,y);

2 dagar ago | 0

Answered
How to average more than 50 3D matrices using nanmean
Here's what I would do, I suppose. It assumes each of your .mat files stores the volume under the name 'a'. Summation=0; NCoun...

2 dagar ago | 2

| accepted

Answered
The best way to code this optimization problem
I have matlab 2013b Because the array sizes are fairly small here, the easiest thing might be to use my func2mat submission to ...

3 dagar ago | 0

Answered
Is there any way to fill this shape?
I=imread('shapes.jpg'); % to extract orange color A=(I(:,:,1) >= 245 ) & (I(:,:,1) <= 255) & ... (I(:,:,2) >= 121 ) & (I(:,:...

3 dagar ago | 0

| accepted

Answered
How to use options in fsolve
I know that i have to do fsolve(@(x) myfunz,x0,options) I don't think so. The exit message says "Equation solved". Another ...

3 dagar ago | 0

Answered
The best way to code this optimization problem
It should be very straightforward using the problem-based solvers in the Optimization Toolbox, https://www.mathworks.com/help/o...

3 dagar ago | 1

Answered
how do i create a random matrix with set size yet the numbers are in a range from 0-9
randi([0,9],4,6) %random integers or 9*rand(4,6) %non-integers

3 dagar ago | 0

| accepted

Answered
Error while using blockproc. Matrix dimensions must agree.
Matrix dimensions must agree. Error in dct (line 76) b = W .* fft(y); It would appear that W and y are not the same size....

4 dagar ago | 1

| accepted

Answered
Form a 3D matrix for a 2d matrix
NewM3D = reshape(ExitVector,size(M3D));

4 dagar ago | 0

Answered
how can i bound rate of changes (dx/dt) in fmincon optimization?
See https://www.mathworks.com/matlabcentral/answers/490758-limit-on-the-change-rate-of-the-variable-in-fmincon-function#answer_...

4 dagar ago | 0

Answered
Limit on the change rate of the variable in fmincon function
You would build linear inequality matrices like the following. E=diff(eye(numel(u))); A=[E;-E]; b=[ub(:);-lb(:)]; %linear ...

5 dagar ago | 1

| accepted

Answered
Multiplication in cell arrays
result = cat(3,precip{:}).*reshape(numbers,1,1,[]); There seems little reason either for precip to be a cell array or to turn t...

5 dagar ago | 0

Answered
Regular expression for 1*1 cell array
c='<string_attribute name="country"><s>CHINA5</s></string_attribute>'; out=extractBetween(c,'<s>','</s>'); >> out{1} an...

5 dagar ago | 1

Answered
Weighted fit with lsqcurvefit and (ideally) multistart?
Just apply whatever weights you want to the objective and to your ydata, fun=@(x,xdata)kinetics_full(x,xdata).*sqrt(weights); ...

5 dagar ago | 0

Answered
Rotate matrix with interp2
This might be what you want. [X,Y]=meshgrid(x-mean(x),y-mean(y));

5 dagar ago | 0

| accepted

Answered
Finding angle of rotations from a given unit vector to rotate a given vector using those angle to align with the previous unit vector
The following might be what you're looking for. It uses my AxelRot utility from the File Exchange https://www.mathworks.com/mat...

6 dagar ago | 0

| accepted

Answered
Nested For Loop for 2D Matrix
I vaguely wonder whether you are just re-inventing convolution result = conv2(Matrix,staticMatrix,'valid');

6 dagar ago | 0

Answered
Nested For Loop for 2D Matrix
So then you want to extract random 51x51 submatrices? If so, then, I=sort(randperm(600,51)); J=sort(randperm(1000,51)); sub...

6 dagar ago | 0

| accepted

Answered
The result of rotation matrix rotx(angle) with a coordinate does not give the desired result
Here's what my AxelRot utility gives https://www.mathworks.com/matlabcentral/fileexchange/30864-3d-rotation-about-shifted-axis?...

6 dagar ago | 0

Answered
how can I find the coordinates of the central axis of a river in an image (binary)?
load River C=watershed(bwdist(A))==0; [icoords,jcoords]=find(C); %coordinates of center line imshow(A+C)

6 dagar ago | 2

| accepted

Answered
Count the number of intersections between any two curves
The only general way (i.e., for arbitrary curves) is using the Symbolic Math Toolbox, solve(curve1==curve2)

6 dagar ago | 1

Answered
How to match a number between two characters?
>> str=extractBetween("[180] Windabweichung","[","]") str = "180"

6 dagar ago | 0

| accepted

Load more