what does regular expression do in this solution?
just for decrease solution size?
Test | Status | Code Input and Output |
---|---|---|
1 | Pass |
%%
x = 1881;y_correct = 30;
assert(isequal(yearraey(x),y_correct))
|
2 | Pass |
%%
x = 2014;y_correct = 1;
assert(isequal(yearraey(x),y_correct))
|
3 | Pass |
%%
x = 2015;y_correct = 0;
assert(isequal(yearraey(x),y_correct))
|
4 | Pass |
%%
x = 606;y_correct = 27;
assert(isequal(yearraey(x),y_correct))
|
5 | Pass |
%%
x = 6006;y_correct = 71;
assert(isequal(yearraey(x),y_correct))
|
6 | Pass |
%%
x = 60006;y_correct = 369;
assert(isequal(yearraey(x),y_correct))
|
7 | Pass |
%%
k=zeros(1,15);
for n=1:15
y=2^n+2;
k(n)=yearraey(y);
end
y_correct=[1 1 5 3 11 7 23 15 47 31 95 63 191 127 383];
assert(isequal(k,y_correct))
|
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