Solution 3135561

Submitted on 9 Oct 2020 by mcbirxx

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mcbirxx on 9 Oct 2020

It's called recycling :)

Test	Status	Code Input and Output
1	Pass	x = 1; y_correct = sqrt(3)/4; tolerance = 1e-12; assert(abs(equilateral_area(x)-y_correct)<tolerance)
2	Pass	x = 2; y_correct = sqrt(3); tolerance = 1e-12; assert(abs(equilateral_area(x)-y_correct)<tolerance)
3	Pass	x = 3; y_correct = sqrt(3)*9/4; tolerance =1e-12; assert(abs(equilateral_area(x)-y_correct)<tolerance)

Test

Status

Code Input and Output

Pass

x = 1; y_correct = sqrt(3)/4; tolerance = 1e-12; assert(abs(equilateral_area(x)-y_correct)<tolerance)

Pass

x = 2; y_correct = sqrt(3); tolerance = 1e-12; assert(abs(equilateral_area(x)-y_correct)<tolerance)

Pass

x = 3; y_correct = sqrt(3)*9/4; tolerance =1e-12; assert(abs(equilateral_area(x)-y_correct)<tolerance)

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Problem 2016. Area of an equilateral triangle