Solution 3216523

Submitted on 15 Oct 2020 by Monica R

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Monica R on 15 Oct 2020

simply use pythagoraen theorem

Test	Status	Code Input and Output
1	Pass	a = 1; b = 2; c_correct = sqrt(5); tolerance = 1e-12 ; assert(abs(hypotenuse(a,b)-c_correct)<tolerance);
2	Pass	a = 3; b = 4; c_correct = 5; tolerance = 1e-12 ; assert(abs(hypotenuse(a,b)-c_correct)<tolerance);
3	Pass	a = 5; b = 12; c_correct = 13; tolerance = 1e-12 ; assert(abs(hypotenuse(a,b)-c_correct)<tolerance);

Test

Status

Code Input and Output

Pass

a = 1; b = 2; c_correct = sqrt(5); tolerance = 1e-12 ; assert(abs(hypotenuse(a,b)-c_correct)<tolerance);

Pass

a = 3; b = 4; c_correct = 5; tolerance = 1e-12 ; assert(abs(hypotenuse(a,b)-c_correct)<tolerance);

Pass

a = 5; b = 12; c_correct = 13; tolerance = 1e-12 ; assert(abs(hypotenuse(a,b)-c_correct)<tolerance);

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Problem 2015. Length of the hypotenuse