Neglecting difference between two values if it is very small so that value1= value2

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I am working on a dataset. After some eigendecompostion process. I realise the difference between my values are as small as 1.8097e-14 which is my further implementation process.
Example
data1(1:10) = 0 0.1502 0.2970 0.4371 0.5673 0.6845 0.7863 0.8702 0.9343 0.9773
data2(1:10) = -0.0000 0.1502 0.2970 0.4371 0.5673 0.6845 0.7863 0.8702 0.9343 0.9773
C= data1(1:10)-data2(1:10)
C =
1.0e-12 *
0.0862 0.1227 0.1545 0.0772 0.1019 0.1178 -0.0174 0.0048 0.0170 0.0181
How do I code that the these difference be neglected so that values in data1 & data2 will be equal since the difference is very small

Answers (1)

Fangjun Jiang
Fangjun Jiang on 28 Jul 2021
Edited: Fangjun Jiang on 28 Jul 2021
To compare element by element, abs(C) < Tolerance
To compare the two vectors as a whole, all(abs(C) < Tolerance)
or use
ismembertol(C,0,Tolerance)
  7 Comments
Fangjun Jiang
Fangjun Jiang on 29 Jul 2021
I guess you could to that. The solution is clear, do whatever to get the result you need.

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