How can i changethe value at a position in an array

1 view (last 30 days)
Hello, i wanted to cahnge some values in an array but could not do it, can you help me? Thanks in advance.
k=zeros(201);
k(0)=0;
k(101)=1;
k(201)=2;

Accepted Answer

Star Strider
Star Strider on 20 Jun 2021
The ‘k’ array is a (201x201) array of zeros. The code likely works correctly, however using a single index into an array uses linear indexing. To understand the row and column assignments for element 101 and 201, use the ind2sub function:
k = zeros(201)
k = 201×201
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
k(101)=1;
[r1,c1] = ind2sub(size(k), 101)
r1 = 101
c1 = 1
k(r1,c1)
ans = 1
k(201)=2;
[r2,c2] = ind2sub(size(k), 201)
r2 = 201
c2 = 1
k(r2,c2)
ans = 2
See the documentation on Matrix Indexing for details. .

More Answers (0)

Tags

Products


Release

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!