Sort Columns by ascending order while maintaing cell values in place for every row
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I have a code that will create a matrix (32xM) with each column being a random permutation of 32.
for k =1:100 %For however many trials (100 in this case)
p(:,k)= randperm(32); %Create a permutation of 32 in each column
end
Is there a way to now order the random permutations in ascending order without losing the order of permuation? To clarify, can I order an entire column to sort based on its first cell value in ascending order? This should result in the random permutations being organized from least to greatest.
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Answers (1)
Scott MacKenzie
on 3 Jun 2021
Edited: Scott MacKenzie
on 3 Jun 2021
Hmmm, I think this works...
for k =1:100 %For however many trials (100 in this case)
p(:,k)= randperm(32); %Create a permutation of 32 in each column
end
q = sortrows(p',1:32);
q = q'
Here's an example with smaller values to show the sorting result:
for k =1:8
p(:,k)= randperm(5);
end
p
q = sortrows(p',1:5);
q = q'
p =
3 1 5 5 1 2 1 3
4 4 3 3 5 5 4 4
1 5 2 2 4 4 3 2
2 2 4 1 3 3 2 1
5 3 1 4 2 1 5 5
q =
1 1 1 2 3 3 5 5
4 4 5 5 4 4 3 3
3 5 4 4 1 2 2 2
2 2 3 3 2 1 1 4
5 3 2 1 5 5 4 1
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