deleting part of a string

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andrew on 17 Jul 2013
Commented: arvind ramasamy on 11 Jul 2018
I have a string that I only want part of how do I get rid of the part I do not need.
for example:
original new
dogcat_1_12334 ==>dogcat
dogcat_2_13342 ==>dogcat
dogcat_3_13442 ==>dogcat

Answers (3)

Jan on 17 Jul 2013
s = 'dogcat_1_12334';
t = strtok(s, '_');
  1 Comment
arvind ramasamy
arvind ramasamy on 11 Jul 2018
I make a serial communication with an arduino and get the data of accelerometer mag and gyro values my data comes in as a string. 's' is the object i created for serial communication
data =fscanf(s,%s) % gives me the data from the arduino
i want my vector size to be 500. so when I run it in for loop
for i= 1:50
data =fscanf(s,'%s');
my output is: data = initializationsuccesful!
data = ax:123ay:23az:1234gx:23gy:50gz:43mx:23my:123mz:234
and goes on.
I use,
A_x(:,i) = str2num(data(:,4:8))
to get my vector. but since 'initializationsuccessful!' is not a number i am unable to form my vector. so how can I do it ???? this is my question

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Evan on 17 Jul 2013
Edited: Evan on 17 Jul 2013
Here's another answer, just in case the characters you want to keep don't fall in sequential order. If they don't, regexp with a "match" argument will split them up into separate cells. regexprep however, will just remove the unwanted parts.
ex1 = 'dogcat_1_12334'
ex2 = 'dog_1_12334_cat'
>> regexprep(ex1,'[^a-z]','')
ans =
>> regexprep(ex2,'[^a-z]','')
ans =
To modify this for more general cases, just change the string argument '[^a-z]'. Put any characters than you want to keep from being removed in the brackets []. The carat ^ operator specifies that "everything but" what is present in the brackets is modified to the second string argument, ''. Since '' is blank, that means anything not in the [^] will be removed.

Azzi Abdelmalek
Azzi Abdelmalek on 17 Jul 2013
Edited: Azzi Abdelmalek on 17 Jul 2013
  1 Comment
Azzi Abdelmalek
Azzi Abdelmalek on 17 Jul 2013
in case you have numbers and characters

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