plot simple 2D-surface from 2D-vector valued function

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It's really frustrating me that I manage to transfer it into 3D and not 2D. Her'es what I'm talking about:
I got a function f: (u,v) ->(u*sin(v),u*cos(v),u^2) where u in (0,1) and v in (0,2*pi)
What's working flawlessly:
[u,v] = meshgrid(linspace(0,1),linspace(0,2*pi));
x = u.*sin(v); y = u.*cos(v); z = u.^2;
mesh(x,y,z)
But what IF I just want to plot x and y without z? According to my imagination a filled circle should be the outcome.
mesh(x,y)
is not supporting that point of view
  2 Comments
Niklas Kurz
Niklas Kurz on 2 May 2021
What also seems to work:
u = linspace(0,1); v = linspace(0,2*pi)
v = v';
x = u.*sin(v); y = u.*cos(v);
plot(x,y)
But also not right what I'm striving for because points are connected as line.

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Accepted Answer

Scott MacKenzie
Scott MacKenzie on 2 May 2021
Edited: Scott MacKenzie on 3 May 2021
Seems you just want the points and not the lines connecting the points. In that case, just add a line specifier to plot to specify plotting just the points:
u = linspace(0,1); v = linspace(0,2*pi)
v = v';
x = u.*sin(v); y = u.*cos(v);
plot(x,y,'.'); % '.' is a line specifier -- just the points are plotted
Here's the output, zoomed in a bit to show that only the points are plotted:
Having just re-read your original question, perhaps you want a "filled circle". In that case, use patch instead of plot:
u = linspace(1, 0); % NOTE: largest circle first
v = linspace(0, 2*pi);
v = v';
x = u.*sin(v);
y = u.*cos(v);
c = 1:100;
patch(x, y, c, 'edgecolor', 'none');
The circle edges are turned off to prevent the lines from dominating the visual result. Note as well that the circle patches are created largest to smallest. This is needed so new circles are visible on top of previous circles.

More Answers (1)

Adam Danz
Adam Danz on 3 May 2021
Perhaps you're just looking for a top-down view of the 3D axes
[u,v] = meshgrid(linspace(0,1),linspace(0,2*pi));
x = u.*sin(v); y = u.*cos(v); z = u.^2;
mesh(x,y,z)
view(2) % <---- set view
xlabel('x axis')
ylabel('y axis')

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