how to sum a result with multiple values

11 views (last 30 days)
a=[170;115;110;70;80;100;140;65;80;99;48];
b=[40;20;27;20;18;20;30;14;13;22;17];
k=a./(a-b)
k results in 11 values as intended, i'd like to do Kmed=k/11 how can i add the 11 values of k=a./(a-b) into 1 value without having to manually insert all 11 values and then divide by 11 ?

Accepted Answer

madhan ravi
madhan ravi on 13 Apr 2021
Edited: madhan ravi on 13 Apr 2021
You literally answered your own question, just use sum()
help sum
SUM Sum of elements. S = SUM(X) is the sum of the elements of the vector X. If X is a matrix, S is a row vector with the sum over each column. For N-D arrays, SUM(X) operates along the first non-singleton dimension. S = SUM(X,'all') sums all elements of X. S = SUM(X,DIM) sums along the dimension DIM. S = SUM(X,VECDIM) operates on the dimensions specified in the vector VECDIM. For example, SUM(X,[1 2]) operates on the elements contained in the first and second dimensions of X. S = SUM(...,OUTTYPE) specifies the type in which the sum is performed, and the type of S. Available options are: 'double' - S has class double for any input X 'native' - S has the same class as X 'default' - If X is floating point, that is double or single, S has the same class as X. If X is not floating point, S has class double. S = SUM(...,NANFLAG) specifies how NaN (Not-A-Number) values are treated. The default is 'includenan': 'includenan' - the sum of a vector containing NaN values is also NaN. 'omitnan' - the sum of a vector containing NaN values is the sum of all its non-NaN elements. If all elements are NaN, the result is 0. Examples: X = [0 1 2; 3 4 5] sum(X, 1) sum(X, 2) X = int8(1:20) sum(X) % returns double(210), accumulates in double sum(X,'native') % returns int8(127), because it accumulates in % int8 but overflows and saturates. See also PROD, CUMSUM, DIFF, ACCUMARRAY, ISFLOAT. Documentation for sum doc sum Other functions named sum codistributed/sum duration/sum sym/sum timeseries/sum dlarray/sum gpuArray/sum tall/sum

More Answers (0)

Categories

Find more on Get Started with MATLAB in Help Center and File Exchange

Products


Release

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!