Flipping a curve to match another in a figure

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Ashik Rahman on 7 Apr 2021
Edited: DGM on 7 Apr 2021
Is it possible to flip the top curve to match the other one at bottom to match the red circled area. I have attached the dataset if you want to try. DGM on 7 Apr 2021
Edited: DGM on 7 Apr 2021
I'm not really sure what you're expecting, but you can flip it easy enough.
plot(XX,YY,'b'); hold on;
xmax=max(XXXX);
ymax=max(YYYY);
plot(xmax-XXXX,ymax-YYYY,'k'); Though I have a feeling that simple flipping isn't a good solution. Consider that the two series used to share endpoints. Perhaps it would be better to flip across a line connecting the endpoints:
Using that example:
%% using line reflection
clear; clc; clf
plot(XX,YY,'b', 'DisplayName', 'XX,YY'); hold on;
x=XXXX; % the example script uses these names
y=YYYY;
xx=[max(x) min(x)];
yy=[min(y) max(y)];
slope = (yy(2)-yy(1))/(xx(2)-xx(1))
intercept = yy(1)-xx(1)*slope
% Calculate slope and y-int of line perpendicular to reflection line
perpSlope = -1/slope;
yInt = y - perpSlope.*x;
% Find where each point (x,y) crosses the reflection line
% These should all lie on the reflection line
xintersect = (yInt-intercept)/(slope-perpSlope);
yintersect = slope*xintersect + intercept;
% Shift each (x,y) point to the origin and rotate 180 deg
xs = x - xintersect;
ys = y - yintersect;
xr = xs * cos(pi) - ys * sin(pi);
yr = xs * sin(pi) + ys * cos(pi);
%shift back to original positions, but reflected.
xFinal = xr + xintersect;
yFinal = yr + yintersect;
% Plot the data
plot(xFinal, yFinal, 'k', 'DisplayName', 'ReflectedData')
rh = refline(slope, intercept);
rh.DisplayName = 'ReflectionLine';
legend() R2021a

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