How to find the sum of values of a function at mid point of every subinterval?
1 view (last 30 days)
Show older comments
I am trying to run this code but don't know how to write code for finding value of function F at mid point of subinterval say, if my interval is [ti, ti+1] for i=0,1,2, n. and need to find sum of functional value at every (ti +ti+1)/2. I need to do it for Rsum2 in this code.
clc; clear all; format long
%%%%%%%%%%%%%%%%%%%%%%%%%%
alpha=0.8;% fractional index
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
TN=1 % time
N=10
T0=0
tau=TN/N
T=[T0:tau:TN]
X0=0
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
X(1)=X0
F =@(X,T)=X+T
for n=0:N-1
Rsum=0;
for j=1:1:n+2
Rsum=Rsum+2*F (j)
end
Rsum2=0;
for j=1:1:n+1
Rsum2=Rsum2+4*F (j+1/2)
end
X(n+2)=X(1) +(tau^alpha)*Rsum + (tau^alpha)*Rsum2
end
0 Comments
Accepted Answer
Matt J
on 20 Mar 2021
Edited: Matt J
on 20 Mar 2021
If your function is vectorized, like in the following example, it is quite simple:
fun=@(tm) tm.^2+ sqrt(tm); %A vectorized function
n=8;
t=sort(rand(1,n)) %interval end points t(i)
tmid = t(1:end-1)/2 +t(2:end)/2 %interval mid-points
result = sum(fun(tmid))
3 Comments
More Answers (0)
See Also
Categories
Find more on Calculus in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!