output will not suppress even with a semi colon
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Hello I am having an issue with a code. I have a semi colon everywhere in my code yet it still outputs the answer when I don't want it to. I have the code below. It will always outputs j and I have no idea how to make it stop. Any help would be appreciated! Thank you in advance.
[ j, out, Matches ] = Make_Numbers(Test_Sum, DATA, Thold, Bonusflag, n)
out = DATA;
[a,b] = size(DATA);
out = [out cellstr(num2str((1:a)'))];
start = 1;
stop = a;
e = 1;
for i = 1:e;
Test_Sum = max(Test_Sum, Test_Sum');
[~,Matches] = find_matches(Test_Sum,Thold);
sub_Graph = find_subgraph(Matches);
disp(num2str(length(sub_Graph)));
%Strength Function
if(Bonusflag)
STR = strength(sub_Graph, Test_Sum);
[sub_Graph,peoplenum] = refineID(STR,DATA(start:stop,35), AAA,
sub_Graph);
disp([num2str(peoplenum) ' members']);
end
[c,~] = size(Test_Sum);
temp = cell(c,1);
[~,d] = size(sub_Graph);
check = true(d,1);
for j = 1:d;
target = sub_Graph{1,j};
[~,h] = size(target);
for k = 1:h;
temp{target(1,k), 1} = ([num2str(n,'%02d') '-' num2str(j,'%04d')]);
check(target(1,k),1) = false(1,1);
end
end
if(sum(check))
error('NOT ALL PERSONS USED');
end
out(start:stop, b+1) = temp;
end
end
0 Comments
Accepted Answer
Roger Stafford
on 28 May 2013
Edited: Roger Stafford
on 28 May 2013
Semicolons will not suppress the actions of the 'disp' function. You need to remove them if you don't want to see an output from them.
Also I notice you don't have a semicolon after the first line and the "function" designation is not there. That will produce an output as it stands.
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