MATLAB Answers

Using Variable in Legend in for loop

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ercan duzgun
ercan duzgun on 7 Feb 2021
Answered: Srivardhan Gadila on 10 Feb 2021
I want to use variable in legend in a scatter plot. I found similar questions about variable in legend. However, they are not in a for loop. I need it in a for loop. How can I do this? My code is :
close all;clear all; clc;
x=-20:5:20;
y=-20:5:20;
z=40:5:80;
[X,Y,Z]=meshgrid(x,y,z)
h=0;
for i=1:1:length(x)
for j=1:1:length(y)
for k=1:1:length(z)
h=h+1
M(h,:)=[X(i,j,k), Y(i,j,k), Z(i,j,k)];
N(h)=bul_poz_real_cozum_sayisi([M(h,1); M(h,2); M(h,3) ],[0;0;0]);
end
end
end
NN = unique(N); NN_length=length(NN);
BB = unique(B); BB_length=length(BB);
S=[10 10 20 20 30 ];
figure; hold on;
for i = 1:NN_length
NNN = (N == NN(i)); % Without FIND: faster logical indexing
scatter3(M(NNN, 1), M(NNN, 2), M(NNN, 3), S(i),'filled');hold on;
str = {strcat( num2str(NN(i)), 'Solutions')};
legend(str{:})
end
xlim([x(1),x(end)]);ylim([y(1),y(end)]);zlim([z(1),z(end)]);
axis equal; grid on;rotate3d;view(3);
It only writes the last legend, and deletes the preious legend. NN=[4 6 8 10 12]. So the legend should be like this:
  • 4 Solutions
  • 6 Solutions
  • 8 Solutions
  • 10 Solutions
  • 12 Solutions

Answers (1)

Srivardhan Gadila
Srivardhan Gadila on 10 Feb 2021
Refer to Add Legend to Graph for more information.
You can make use of the 'DisplayName' name value pair argument as follows:
x = 1:4;
figure
hold on
for i=1:4
z = linspace(0,4*pi,250)/i;
x = 2*cos(z) + rand(1,250);
y = 2*sin(z) + rand(1,250);
scatter3(x,y,z,'filled','DisplayName',num2str(i))
end
legend

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