Index exceeds the number of array elements: in case of for loop.

1 view (last 30 days)
I have this code where simple permutation will be performed , but i am getting an error message as "Index exceeds the number of array elements (8)."
k4='00000000000000000000000000000000';
k4=reshape(k4,8,[]);
k4=bin2dec(k4);
Perm=[0 4 8 12 16 20 24 28 32 36 40 44 48 52 56 60 ...
1 5 9 13 17 21 25 29 33 37 41 45 49 53 57 61 ...
2 6 10 14 18 22 26 30 34 38 42 46 50 54 58 62 ...
3 7 11 15 19 23 27 31 35 39 43 47 51 55 59 63];
for i = 1:8
j4(i)=k4(Perm(i)+1);
end
  3 Comments
Maria Imdad
Maria Imdad on 9 Dec 2020
how should i update my loop, so that it permutes all of the 8 values in k4?
David Hill
David Hill on 9 Dec 2020
k4 is all zeros. What do you mean by permuting all 8 values? Provide an example.

Sign in to comment.

Answers (1)

Timo Dietz
Timo Dietz on 9 Dec 2020
Edited: Timo Dietz on 9 Dec 2020
k4 has 8 members.
But the third member of Perm is 8. So plus one leads to 9 which is more than k4 contains k4(Perm(i)+1) = k4(9);
To me it's not clear what you try to do. Could you please give an example of the expected result?
Btw., are you aware of the built-in "permute" function?
  3 Comments
Timo Dietz
Timo Dietz on 9 Dec 2020
Edited: Timo Dietz on 9 Dec 2020
If you just want to rearrange k4, as I wrote, "permute" is the function you need.
But certainly you can't use a higher index in your Perm array than present in k4.

Sign in to comment.

Categories

Find more on Elementary Math in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!