How to create and plot a Gaussing function?

26 views (last 30 days)
Hello ,
i want to create a 2D Gaussian function 9x9 and sigma =0.7 using this type :
Here is my code:
sigma=0.7;
nx=9;
ny=9;
[x,y]=meshgrid(1:nx,1:ny);
G=(0.5/(pi.*(sigma.^2))).*exp(-0.5.*((y.^2+x.^2)./(sigma.^2)));
Then i was asked to take the Gaussian function G and compute its fast fourier transform by using fft2()
G_fft=fft2(G);
Finally by using mesh() i was asked to compare the 2 results .
figure();
mesh(G);
figure();
mesh(G_fft);
The problem here is that in the first case (mesh(G)) i am getting a big edge(which i dont know if its right) and in the second case i am getting this error : X, Y, Z, and C cannot be complex. (problem in the line mesh(G_fft) because G_fft has complex numbers due to fourier transform).
Can comeone tell me what is wrong here?

Accepted Answer

VBBV
VBBV on 7 Dec 2020
Edited: VBBV on 7 Dec 2020
%true
sigma=0.7;
nx=9;
ny=9;
[x,y]=meshgrid(-nx:0.5:nx,-ny:0.5:ny);
G=(0.5./(pi.*(sigma.^2))).*exp(-0.5.*((y.^2+x.^2)./(sigma.^2)));
G_fft=fft2(G);
figure(1);
mesh(x,y,G);
figure(2);
mesh(x,y,abs(G_fft));
Use both positive and negative values for meshgrid to get Gaussian shape as above. Use also _abs_instead of real value e
  1 Comment
Gn Gnk
Gn Gnk on 7 Dec 2020
Perfect thank you so much !!
Just a quick notice :
nx and ny should be equal to 2 in order for G to be 9x9 .
Can you explain why the plots appear to be opposite (i think)

Sign in to comment.

More Answers (0)

Categories

Find more on Fourier Analysis and Filtering in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!