how can i reshape an indexed vector

Hello,
I have the following problem:
Q % e.g. 300 x 300 matrix
M % e.g. 300 x 300 matrix
omega=find(Q); % omega becomes a 86567x1 vector
b= M(omega);% b is also a 86567x1 vector
Is there a way to reshape b to have the same dimension as Q?

 Accepted Answer

Ameer Hamza
Ameer Hamza on 2 Nov 2020
Edited: Ameer Hamza on 2 Nov 2020
Q has 90000 elements, whereas b has 86567 elements. Direct reshaping is not possible. I guess you are trying to do something like this
Q % e.g. 300 x 300 matrix
M % e.g. 300 x 300 matrix
b = M.*Q
It an element in Q is zero, then it will multiply the corresponding element in M with 0 too.

3 Comments

yes but the partiuclar algorithm im using (SVT) doesnt allow this M.*Q form. it wants a vector of the form b= M(omega). So after running the algorithm. I just want to reconstruct image.
Ok, In that case, you can do something like this
Q = randi([0 1], 300); % e.g. 300 x 300 matrix
M = rand(300); % e.g. 300 x 300 matrix
omega=find(Q); % omega becomes a 86567x1 vector
b = M(omega);% b is also a 86567x1 vector
% apply your algorithm on b vector
B = zeros(size(Q));
B(Q~=0) = b;
B has same size as Q.
Thanks a lot man. I guess its my algorithm that has issues. your fix makes sense. only i didnt get the desired image i wanted. Thanks all the same.

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More Answers (1)

Whn you use find you will get the global indices in the form of column array...YOu can use logical indexing, so that you can have your matrix dimensions intact with 1 where condition is obeyed and 0 where condition is not.
omega = Q~=0;

1 Comment

This could be useful in future. Now i understand how the find works. thanks!

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Asked:

on 2 Nov 2020

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on 2 Nov 2020

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