How to efficiently match the zeros of 1 matrix with another
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Hello, I am solving an inverse problem through simulated annealing, but the loop I use to match the zeros of my data with zeros in my model (so that the inversion is only solved for non-zero elements of data) is making my code very inefficient.
D is the data matrix of dimensions 26x12x160 with many zeros
S is my model, it has the same dimensions, I want it to have zeros where D has zeros
I am using the following loop for this
for i=1:length(D(:,1,1))
for j=1:length(D(1,:,1))
for k=1:length(D(1,1,:))
if D(i,j,k)==0
S(i,j,k)=0;
end
end
end
end
Is there a more efficient way to do this? Maybe a way to kill 1 loop? I am very inexperienced with efficient coding...
Thanks in advance
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Accepted Answer
More Answers (1)
Bruno Luong
on 27 Oct 2020
Edited: Bruno Luong
on 27 Oct 2020
The 3 for-loops can be shrink down to
S(D==0) = 0;
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