Error using unique command

I have two values
A = [1000 16000 100000 30000 2000]
B = [150 100 4000 5000 2000];
I used code below to get the Sorted value of B according to A:
[ii jj k] = unique(A);
B = unique(B);
P = B(k);
C = [100 4000 2000 5000 150];
If my values of A are from -400 to 400 and and values of B are from -100 to 100 I get the error :
Index exceeds Dimension
Please provide assistance.

 Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 24 Nov 2012
Edited: Azzi Abdelmalek on 24 Nov 2012
Edited
A=[1000 16000 100000 30000 2000]
B=[150 100 4000 5000 2000];
[~,idx]=sort(A)
[~,idx1]=sort(idx)
C=B(idx1)

21 Comments

Pat
Pat on 24 Nov 2012
But Azzi those sizes are same ,if not that code can you suggest some other code please
Pat
Pat on 24 Nov 2012
Azzi i am getting the same error
If they are the same length, you can't get an error, If they are not the same length you can't use P=B(jj), you can use P=A(jj)
Pat
Pat on 24 Nov 2012
Azzi same error
Index exceeds matrix dimensions.
Error in ==> sample at 64 P=B(jj)
if anything worng in that code,can you assist me with another code please
Pat
Pat on 24 Nov 2012
Anothet thing Azzi my both value size of A and B are same say 300x1
i used
g=unique(A);its size is 224x1
g1=uinque(B);its size is 87x1
Pat
Pat on 24 Nov 2012
size of A is 300x1
size of B is 300x1
Ok, have you changed your code orfer to
P=B(k) % then
B=unique(B);
Pat
Pat on 24 Nov 2012
I have done everthing what u have posted
Post your full code
YEs Azzi i get error
Index exceeds matrix dimensions.
Error in ==> sample at 64 P=B(k)
Pat
Pat on 24 Nov 2012
i changed even same error
Index exceeds matrix dimensions.
Error in ==> sample at 64 P=B(jj)
My code
A=csvread(''); 300x1
B=csvread(''); 300x1
Cw=A;
Sw=A;
for i=1:length(Cw)
if (Cw(i)<12 && Cw(i)>-12)
Cw(i)=0;
end
end
for i=1:length(Sw)
if (Sw(i)<12 && Sw(i)>-12)
Sw(i)=0;
end
end
A=Cw;
B=Sw;
if length(A)<length(B)
S=length(B)-length(A);
S1=zeros(S,1);
A=[A;S1];B;
elseif length(A)>length(B)
S=length(A)-length(B);
S1=zeros(S,1);
B=[B;S1];A;
else
A;B;
end
Cw=A;
Sw=B;
[r c]=size(Cw)
[r1 c1]=size(Sw)
Cw=double(Cw);Sw=double(Sw);
A=[];B=[];
A=Cw;B=Sw;
[ii jj k]=unique(A);
B=unique(B);
P=B(jj)
B=unique(B);
Azzi Abdelmalek
Azzi Abdelmalek on 24 Nov 2012
Edited: Azzi Abdelmalek on 24 Nov 2012
Pat, remove the third line (counting from the last line) B=unique(B); You can even use B(k) if that's what you need
Pat
Pat on 24 Nov 2012
ok Azzi now it works ,the thing is the size of B differ which is B=unique(B); it is just 110x1 , after the same i should get same size ,why do i get different size,
Try this to understand
A=[1 1 1 2 2 12451];
[ii jj k]=unique(A)
check ii, jj and k
Pat
Pat on 24 Nov 2012
Thanks a lot Azzi ,i understand the concept ,even i perform B(k) the size varies,please provide a different code because that unique command is making the size less,in which i have problem in performing other steps
But I don't know what do you want to compute?
A=[1000 16000 100000 30000 2000]
B=[150 100 4000 5000 2000];
Sorting B according to A ,so i got output from above code as
C=[100 4000 2000 5000 150],minimum value of B comes under minimum value of A,,,,,,2nd minimum of B comes under 2nd minmum of A.........finally maximum of B comes under maximum of A
Pat
Pat on 24 Nov 2012
so finallu C will have same size of A and B
or maby it's this
A=[1000 16000 100000 30000 2000]
B=[150 100 4000 5000 2000];
[~,idx]=sort(A)
[~,idx1]=sort(idx)
C=B(idx1)
Pat, look at my edited answer

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More Answers (2)

Salil Goel
Salil Goel on 24 Nov 2012

0 votes

Are you making sure that the size of A and B is same when values in A are from -400 to 400 and B from -100 to 100? If not, then obviously you would get this error.
Matt Fig
Matt Fig on 24 Nov 2012
Edited: Matt Fig on 24 Nov 2012
% Sort B the same way A is sorted.
% We only need two calls to SORT.
[~,J] = sort(A);
BSA = sort(B);
J(J) = 1:length(A);
BSA = BSA(J) % This is B, sorted the same way A originally was.

5 Comments

Pat
Pat on 29 Nov 2012
Thanks Fig,if there are unique and negatve values must be done
Pat can you post an example
A=[120 150 12 10 36 25 ];
B=[2 9 1 6 8 10];
out=[9 10 2 1 8 6]
but no idea if it consists of negative and unique values
What is the difference with the previous example?
No difference as u said i have posted an example..another problem am facing Azzi is that if i use
Ew1 = dec2bin(mod(2^16+Ew,2^16)),my all values gets converted to 1111111111111111
y i get all value as one,Ew constsist of values from -32768 to 32767

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