NEED HELP ON MATRIX MANIPULATIONS
1 view (last 30 days)
Show older comments
Consider a matrix
A= 21 14 7 0
18 11 4 3
15 8 1 6
12 5 2 9
9 2 5 12
6 1 8 15
3 4 11 18
0 7 14 21
My objective is to reach from base value 0 to top value 0 as underlined for dynamic time warp algorithm traversal by parsing through the smallest element of each row.
A= 21 14 7 0
18 11 4 3
15 8 1 6
12 5 2 9
9 2 5 12
6 1 8 15
3 4 11 18
0 7 14 21
The cost assignment can be defined as find the smallest element in each column :
1| 21 14 7 0
0| 18 11 4 3
1| 15 8 1 6
0| 12 5 2 9
0| 9 2 5 12
1| 6 1 8 15
0| 3 4 11 18
1| 0 7 14 21
So cost= 1 0 1 0 0 1 0 1
Cost assignment concept:
assign 1 whenever there's a smallest single unique element in the row .
Assign 0 whenever no smallest element is present or when multiple smallest same elements are present in the same row or column,then first instance should be zero and next to be 1 i.e. for example
1| 20 15 10 5 0
1| 16 11 6 1 4
1| 12 7 2 3 8
0| 8 3 2 7 12
1| 4 1 6 11 16
1 | 0 5 10 15 20
0 Comments
Accepted Answer
KSSV
on 16 Dec 2019
A = [ 21 14 7 0
18 11 4 3
15 8 1 6
12 5 2 9
9 2 5 12
6 1 8 15
3 4 11 18
0 7 14 21];
m = min(A,[],2) ;
cost = m == 0 | m == 1 ;
More Answers (0)
See Also
Categories
Find more on Creating and Concatenating Matrices in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!